Based on the graph given, it can be deduced from the computation that the value of y will be -8.
Point C is given as (-10 , -2) and D = (10 , 6)
The Slope of line CD = ( 6 - (-2) /( 10 - (-10) = 8/20 = 2/5
Since EF is parallel to line CD
, the slope of EF = 2/5
Equation y = (2/5)x + c
5y = 2x + 5c
It passes through F ( 6 , -4)
= 5(-4) = 2*6 + 5c
= -20 = 12 + 5c
5c = -32
5y = 2x - 32
Point E ( - 4 , y)
5y = 2(-4) - 32
5y = -8 - 32
5y = -40
y = -8
Therefore, the value of y is -8.
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To prevent injury while maintaining equipment make sure the equipment is locked out and/or tagged out (i.e., de-energized).
<h3>What does locked-out equipment mean?</h3>
Equipment is locked out when it does not contain any type of change that may affect the security of a device.
This task (locked out) is fundamental to avoid any safety problems associated with a device.
In conclusion, to prevent injury while maintaining equipment make sure the equipment is locked out and/or tagged out (i.e., de-energized).
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Answer:
I hope this answers the question
Explanation:
Implementation of firewall
installation of anti-virus software