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Delvig [45]
3 years ago
12

You have $5 and earn $1.75 for each roll of wrapping paper you sell. Write an equation in two variables that represents the tota

l amount A (in dollars) you have after selling r rolls of wrapping paper
Computers and Technology
1 answer:
qaws [65]3 years ago
3 0

Answer:

A = 5 + 1.75r

Explanation:

Amount you have = $5

Earning per roll of wrapping paper = $1.75

Let

r = number of rolls of wrapping paper

A = Total amount earned

A = 5 + 1.75r

Equation that represents the total amount A (in dollars) you have after selling r rolls of wrapping paper is

A = 5 + 1.75r

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Which of the following declares an abstract method in an abstract C++ class? (Points : 2) public: void print();
Dahasolnce [82]

Answer:

public: virtual void print()=0;

Explanation:

An abstract class contains a pure virtual function. Pure virtual class cannot be instantiated but it can be subclassed and the subclass can provide an implementation of the function.

A virtual function declaration in the class is preceded by the virtual keyword. For example, virtual void print();

A pure virtual function declaration is followed by '=0;'

public: virtual void print()=0;

4 0
3 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

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}

8 0
3 years ago
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vfiekz [6]

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4 0
3 years ago
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seraphim [82]
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3 0
3 years ago
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Westkost [7]

Answer:

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Explanation:

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6 0
2 years ago
Read 2 more answers
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