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mart [117]
2 years ago
5

Plzzzz help I’ll mark you

Mathematics
1 answer:
Lyrx [107]2 years ago
3 0

Answer:

3/10 liters more

Step-by-step explanation:

8/10 - 5/10 = 3/10

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Find length of each side
IgorLugansk [536]

Option b: 10 in, 18.5 in, 31.5 in.

Explanation:

The three sides of a triangle are 2y+1, 3y+5 and 7y

The perimeter of the triangle is 60 in.

Since, Perimeter = all sides of the triangle

Let us add all the three sides to determine the length of each side.

Perimeter=2y+1+3y+5+7y

Substituting the value of Perimeter and simplifying, we get,

60=12y+6\\54=12y\\4.5=y

Substituting y=4.5 in the three sides of the triangle 2y+1, 3y+5 and 7y, we get,

2y+1=2(4.5)+1=10 in

3y+5=3(4.5)+5=18.5 in

7y=7(4.5)=31.5 in

Thus, the lengths of each side are 10 in, 18.5 in, 31.5 in.

8 0
3 years ago
Jason sells computer software. He earns a base salary of $2,766.79 per month. In addition, he earns 9% of his total monthly sale
ipn [44]
Let's start with saying he earned 2766.79. He he also earns 9% of his sales.

9% of something is just .09 multiplied by that something. So if he earns 9% of 3743.37 plus the 2766.79, then we can say

y= 0.09 * 3743.37 + 2766.79
y = 3,103.69
5 0
3 years ago
How can you approximate the square root of 30?
Ierofanga [76]
You can approximate the square root of 30 by taking the square root of a number close to it. This is called local linearization. You can take the square root of 36, which is 6, and the square root of 25, which is 5, and state that the square root of 30 is approximately somewhere between 5 and 6
5 0
3 years ago
Adele, Barbara and Colette share $680 in the ratio 9 : 7 : 4. Calculate the amount that Barbara and Collette each receives.
anzhelika [568]

Answer:

​ i hope this helps

Step-by-step explanation:

6 0
2 years ago
Limit xtens to 0 x^2logx^2 what is the ans of interminate forms?
GarryVolchara [31]

Rewrite the limit as

\displaystyle\lim_{x\to0}x^2\log x^2=\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}

Then both numerator and denominator approach infinity (with different signs, but that's not important). Applying L'Hopital's rule, we get

\displaystyle\lim_{x\to0}\frac{\log x^2}{\frac1{x^2}}=\lim_{x\to0}\frac{\frac2x}{-\frac2{x^3}}=\lim_{x\to0}-x^2=\boxed{0}

7 0
3 years ago
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