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Viktor [21]
3 years ago
7

Give that the point (15,-11) is on the graph of a one-to-one function f(x), find a point on the graph of f^{-1}.

Mathematics
1 answer:
zvonat [6]3 years ago
5 0

Given:

The point (15,-11) is on the graph of a one-to-one function f(x).

To find:

The a point on the graph of f^{-1}.

Solution:

We know that, if the points on the graph of a one to one function are given by (x,y), then the points on the graph of its inverse function are given by (y,x).

In the point (15,-11).

x-coordinate = 15

y-coordinate = -11

In the inverse function,

x-coordinate = -11

y-coordinate = 15

Therefore, the required point on the graph of f^{-1} is (-11,15).

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The table shows the number of games a chess player won in professional competitions, based on the number of games played.
AfilCa [17]

slope  = (25-4)/(30-10)

 slope = 21/20

slope =21/20  

using point slope form

y-y1 = m(x-x1)

y-4 = 21/20 (x-10)

y = 21/20x -21/2 +4

y = 21/20 x -21/2 +8/2

y = 21/20x -13/2


let x=40

y = 21/20 (40) -13/2

y = 42-13/2

y = 35.5 games


If we round the slope to 1

slope =1

using point slope form

y-y1 = m(x-x1)

y-4 = 1 (x-10)

y = 1x -10 +4

y =  x -6


let x=40

y = 40-6

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3 years ago
What value of x will make the question below truw?
MatroZZZ [7]
1/2 (6x - 10) + 10 = 5x - 13

(6x/2) - (10/2) + 10 = 5x - 13

3x - 5 + 10 = 5x - 13

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3 years ago
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