She can measure the temperature, if it will be equal or more than 100, then water is boiling otherwise not.
You should multiply the numbers to get your solution. either 345*25 or 3 and 25
dose this help?
The methods for calculating evapotranspiration from meteorological data require various climatological and physical parameters. Some of the data are measured directly in weather stations. Other parameters are related to commonly measured data and can be derived with the help of a direct or empirical relationship. This chapter discusses the source, measurement and computation of all data required for the calculation of the reference evapotranspiration by means of the FAO Penman-Monteith method. Different examples illustrate the various calculation procedures. Appropriate procedures for estimating missing data are also provided.
Meteorological data can be expressed in several units. Conversion factors between various units and standard S. I. units are given in Annex 1. Climatic parameters, calculated by means of the equations presented in this chapter are tabulated and displayed for different meteorological conditions in Annex 2. Only the standardized relationships are presented in this chapter. The background of certain relationships and more information about certain procedures are given in Annex 3. Annexes 4, 5 and 6 list procedures for the statistical analysis, assessment, correction and completion of partial or missing weather data.
Answer:
a) 
b) 
Step-by-step explanation:
We know that theres a <u><em>linear relationship</em></u> between the rate of the chirping of crickets and the air temperature.
<u><em>The equation of a line is</em></u>:
So, let's name our variables
x= Temperature
y=Rate of the chirping
First of all, we need to find the <u><em>slope</em></u> with the two given points
60ºF , 
80ºF, 
By,
<u>Now, the </u><em><u>equation</u></em><u> between the air temperature and the number of chirps is:</u>
Solving for y,
a)
b) <u>To calculate the </u><u>rate</u><u> at which the crickets chirp when the </u><u>temperature is 102 ºF</u><u> we need to evaluate y(102)</u>
3(2x+4)= 2(4x-1)
6x+12=8x-2
6x-8x= -2-12
-2x=-14
X= 7
Solve for X by simplifying both sides of the equation, then isolating the variable.
