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Fantom [35]
3 years ago
14

The size of angle DEF

Mathematics
1 answer:
Masja [62]3 years ago
8 0

Answer

132 degrees

Step-by-step explanation:

Strategy: Find angle DEB and using that fact that DEB + DEF is 180 degrees to find angle DEF

The sum of the four angles of any quadrilateral is 360 degrees.

Since three angles are given, we can use that to find the fourth.

360-(147+93+72)=size of angle DEB. Solving, you get angle DEB is 48.

Also, knowing that segment BF is a straight line, it means that angle DEB + angle DEF is equal to a straight angle (180 degrees).

DEB+DEF=180

48+DEF=180

DEF=180-48=132 degrees.

Thus, angle DEF is equal to 132 degrees.

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A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
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Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

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y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

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The percentage of the components bought from supplier C that are faulty = 88%

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4 years ago
Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo
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Answer:

a

  P(a | e') =  0.22

  P(b | e') =  0.28

  P(c | e') =  0.33

b

  P(a | e' , d' , b') = 0.57

Step-by-step explanation:

From the question we are told that

   The probabilities are

Supplier  chosen            A                     B                    C            

Probability                P(a) = 0.20       P(b) =  0.25   P(c) =  0.15      

                                       D                      E

                                P(d) =  0.30     P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(a | e') =  \frac{P (a \  and \  e')}{P(e')}

      P(a | e') =  \frac{P (a)}{P(e')}

     P(a | e') =  \frac{P (a)}{1- P(e)}

=>   P(a | e') =  \frac{ 0.20}{1- 0.10}

=>   P(a | e') =  0.22

Generally the new probability of companies B  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(b | e') =  \frac{P (b \  and \  e')}{P(e')}

      P(b | e') =  \frac{P (b)}{P(e')}

     P(b | e') =  \frac{P (b)}{1- P(e)}

=>   P(b | e') =  \frac{ 0.25}{1- 0.10}

=>   P(b | e') =  0.28

Generally the new probability of companies C  being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

P(c | e') =  \frac{P (c \  and \  e')}{P(e')}

      P(c | e') =  \frac{P (c)}{P(e')}

     P(c | e') =  \frac{P (c)}{1- P(e)}

=>   P(c | e') =  \frac{ 0.15}{1- 0.10}

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P(d | e') =  \frac{P (d \  and \  e')}{P(e')}

      P(d | e') =  \frac{P (d)}{P(e')}

     P(d | e') =  \frac{P (d)}{1- P(e)}

=>   P(d | e') =  \frac{ 0.30}{1- 0.10}

=>   P(c | e') =  0.33

Generally the probability that  B, D , E  are not chosen this year is mathematically represented as

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=>       P(N) =  1 - [0.10 +0.25  +0.30 ]

=>       P(N) =  0.35

Generally the probability that A is chosen given that E , D , B  are rejected this year is mathematically represented  as

      P(a | e' , d' , b') =  \frac{P(a)}{P(N)}

=>     P(a | e' , d' , b') =  \frac{0.20 }{0.35 }    

=>     P(a | e' , d' , b') = 0.57

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