Answer:
in triangle ACD and BCE
AC = EC
angle ACD = angle ECB ( COMMON ANGLE).
CB = CD
BY side and side criteria
triangle ACD is congruent to triangle BCE
so angle a is congruent to angle E
hence, proved
15 16 and then 17 to be an equilateral
X = -1. 8 = 4x+12
-4 = 4x
-1 = x
Convert it into the y=a(x-h)+k form and the values of h and k are your vertex.
You can convert by completing the square method.
(4x - 2)* 6(2x + 7)
=(4x - 2)(12x + 42)
= 4x(12x + 42) - 2(12x + 42
= 48x^2 + 168x - 24x - 84
= 48x^2 + 144x - 84 Answer