Answer: Yes, this indicate the proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college.

Step-by-step explanation:

Since we have given that

Hypothesis:

$H_0:p_1=p_2\\\\H_a:p_1>p_2$

n₁ = 100

x₁ = 37

So, $p_1=\dfrac{x_1}{n_1}=\dfrac{37}{100}=0.37$

n₂ = 100

x₂ =47

So, $p_2=\dfrac{47}{100}=0.47$

At 0.01 level of significance, z = 2.33

So, test statistic value would be

$z=\dfrac{p_1-p_2}{\sqrt{\dfrac{p_1(1-p_1)}{n_1}+\dfrac{p_2(1-p_2)}{n_2}}}\\\\z=\dfrac{0.37-0.47}{\sqrt{\dfrac{0.37\times 0.63}{100}+\dfrac{0.47\times 0.53}{100}}}\\\\z=-1.44$

Since, 2.33>-1.44

Hence, we will reject the null hypothesis.

Therefore, Yes, this indicate the proportion of adult americans that attended college and believe in extraterrestrials is higher than the proportion that did not attend college

4 0

3 years ago

You've decided to take 3 steps and randomly choose left or right as the direction each time.

Montano1993 [528]

Answer:

i would say b

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

What is the sum of zeros of the function y=6x^2-x-2 ?

Vsevolod [243]

$y=6x^2-x-2\ \ \ \Rightarrow\ \ \ \Delta=(-1)^2-4\cdot6\cdot(-2)=1+48=49\\\\\Delta>0\ \ \ \Rightarrow\ \ \ exist\ two\ zeros\ of\ the\ function\\\\Vieta's\ formulas:\ \ \ x_1+x_2=- \frac{b}{a} \\\\x_1+x_2=- \frac{-1}{6} = \frac{1}{6}\\\\Ans.\ \ \ The\ sum\ of\ zeros\ is\ \frac{1}{6}$

8 0

3 years ago

Read 2 more answers

Cold weather is hard on Ava’s grandmother, so she is knitting her a striped scarf for her birthday. As Ava was knitting the scar

taurus [48]

Answer:

4.75+0.75

Step-by-step explanation:

6 0

3 years ago