Answer:
The ratio of the area of ∆ABC to the area of ∆DEF is 25/36
Step-by-step explanation:
∆ABC ~∆DEF
∆ABC has a heights of 20 inches, and ∆DEF has a height of 24 inches
The ratio of the height (h1) of ∆ABC to the height (h2) of ∆DEF is:
h1 / h2= (20 inches) / (24 inches)
h1 / h2= 20 / 24
Simplifying the fraction dividing the numerator and the denominator by 4:
h1 / h2= (20/4) / (24/4)
h1 / h2= 5 / 6
The ratio of the area (A1) of ∆ABC to the area (A2) of ∆DEF is:
A1 / A2 = (h1 / h2)^2
A1 / A2 = (5 / 6)^2
A1 / A2 = 5^2 / 6^2
A1 / A2 = 25 / 36
Zero point nine hundred and forty one i hope this helps but im dum so
X^2-y^2
you would get x^2+xy-xy+y^2
the xy and -xy cancel
Answer:
I think its the third one
Step-by-step explanation:
H: hours
45h + 45 = 30h + 75
15h + 45 = 75
15h = 30
h = 2 hours
45 ( 2 ) + 45 = 30 ( 2 ) + 75
90 + 45 = 60 + 75
135 = 135
Therefore the awnser is 2 hours.