Answer:
Step-by-step explanation:
Let the length and breadth of the rectangle be a,b units respectively.
Then the area will be ab square units.
Now if the length of the rectangle is reduced by 5 units and breadth is increased by 2 units then new length and breadth will be (a−5) units and (b+2) units.
Then new area will be (a−5)(b+2).
Then according to the problem,
(a−5)(b+2)−ab=−80
or, 2a−5b=−70.......(1).
Now if length of the rectangle is increased by 10 units and breadth is decreased by 5 units then new length and breadth will be (a+10) units and (b−5) units.
Then new area will be (a+10)(b−5).
Then according to the problem,
(a+10)(b−5)−ab=50
or, 10b−5a=100
or, 2b−a=20
or, 4b−2a=40......(2).
Now adding (1) and (2) we get
−b=−30
or, b=30.
Putting the value of b in (1) we get, a=40.
Now a+b=40+30=70.
Statement Reason
-------------------------------------------------------------------------------------
1. CD=DC Reflexive Property
2. D-midpoint of AB Given
3. AD=BD Definition of Midpoint
4. CD⊥AB Given
5. m<CDA=m<CDB Definition of Perpendicular Lines
6. ΔACD≅ΔBCD SAS
Easy, first turn the factions into deciamls, then so 1.16-7.8=6.64. So, 6.64
Answer:
3) (98.08, 124.16)
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 111.12
Standard deviation = 13.04
Calculate an interval that is symmetric around the mean such that it contains approximately 68% of fines.
68% of the fines are within 1 standard deviation of the mean speed. So
From 111.12 - 13.04 = 98.08 to 111.12 + 13.04 = 124.16
The interval notation in the smallest value before the highest value.
So the correct answer is:
3) (98.08, 124.16)
