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Phantasy [73]
3 years ago
12

Help me fast plz I need help

Mathematics
2 answers:
olasank [31]3 years ago
7 0

Answer:

There Is no problem.

Step-by-step explanation:

I would love to help you once you add a question. Have a blessed day!

FrozenT [24]3 years ago
3 0

Answer:

Whats the question?

Step-by-step explanation:

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Go Math grade 6 standards practice workbook common core edition pages 101 & 102
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3 0
3 years ago
Given parallelogram EFGH with diagonals that intersect at point J, which statement is true? Diagonal segment EG is perpendicular
Anna [14]
E. All of the above are true. 
7 0
3 years ago
Plz help no guessing
Scorpion4ik [409]

The solution to a system of equations is the point that the 2 lines of the graph cross each other.

x = 1 and Y =4

Solution is (1,4)

Answer is C.

8 0
3 years ago
The number of kilograms of water in a human body varies directly as the mass of the body. An 87​-kg person contains 58 kg of wat
katen-ka-za [31]

Answer:

50 kg water.

Step-by-step explanation:

We have been given that the number of kilograms of water in a human body varies directly as the mass of the body.

We know that two directly proportional quantities are in form y=kx, where y varies directly with x and k is constant of variation.

We are told that an 87​-kg person contains 58 kg of water. We can represent this information in an equation as:

58=k\cdot 87

Let us find the constant of variation as:

\frac{58}{87}=\frac{k\cdot 87}{87}

\frac{29*2}{29*3}=k

\frac{2}{3}=k

The equation y=\frac{2}{3}x represents the relation between water (y) in a human body with respect to mass of the body (x).

To find the amount of water in a 75-kg person, we will substitute x=75 in our given equation and solve for y.

y=\frac{2}{3}(75)

y=2(25)

y=50

Therefore, there are 50 kg of water in a 75​-kg person.

3 0
3 years ago
How much of a spice that is 30% salt should be added to 175 ounces of a spice that is 65% salt in order to make a spice that is
klasskru [66]
\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{30\% spice}&x&0.30&0.30x\\
\textit{65\% spice}&175&0.65&(175)(0.65)\\
-----&-----&-------&-------\\
mixture&x+175&0.50&(x+175)(0.50)
\end{array}

so.. as you can see, we use the decimal notation for the percentages... 65% is just 65/100 and 50% is just 50/100 and so on

so.. whatever the salted amounts are, we know they'll add up to (x+175)(0.50)

thus  (0.30x) + (175)(0.65) = (x+175)(0.50)

solve for "x"
5 0
3 years ago
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