(X+Y+Z)/3=84 X,Y,Z IS THE THREE UNKNOWN SCORES.TO KNOW THE TOTAL , MULTIPLY THE 84 BY 3.
84*3=252
(252+H)/4=87 H IS THE FOURTH GRADE HE SHOULD HE IF HE WANTS HIS AVERAGE TO BE 87
87*4=348
252+H=348
H=348-252
H=96
Answer:
B. z Subscript alpha divided by 2 zα/2 = 1.96.
Step-by-step explanation:
We are given that we want to construct a confidence interval. For this, the summary statistics for randomly selected weights of newborn girls:
n = 236,
= 30.3 hg, s = 7.2 hg. The confidence level is 95%.
As we can clearly see here that the population standard deviation is unknown and the sample size is also very large.
It has been stated that when the population standard deviation is unknown, we should use t-distribution but since the sample size is very large so we can use z distribution also as it is stated that at very large samples; the t-distribution corresponds to the z-distribution.
Here,
= level of significance = 1 - 0.95 = 0.05 or 5%
= 0.025 or 2.5%
So, the value of
in the z table is given as 1.96 with a 2.5% level of significance.
Answer:
volume of the prism 5cm
Step-by-step explanation:
Answer:
Let's say someone is selling lemonade at a lemonade stand. The more cups of lemonade this person sells, the more money they get. If 1 cup= $1, then he would get $2 for 2 cups.
Step-by-step explanation:
The price of the lemonade cup and the lemonade cup are a constant of proportionality. They are proportional to each other. The more lemonade you sell, the more money you get.
The graph would be a straight diagonal line. The y would be the money, and the x would be the amount of lemonade sold. Since they are the same and proportional, they would go in a straight line.
For the first example given the answer would be No. you have a 4 mile head start. at the 4 mile line, your friend starts at 8 miles an hour and you start running at 6 miles an hour. basic addition should give the answer. In one hour time, you wouldve ran 6 miles plus the 4 you had as a head start, giving you the 10 miles you needed to reach the finish line. He on the other hand, Biked 8 miles in an hour time. By that time, you had just reached the finish line.
So the answer is no for the first example
For the second example the maths get bit harder. You start at the 5 mile point and you friend starts at the beginning point. You only need 5 miles to win, and your friend needs double (its actually more than double, because if it was perfectly doubled, you would tie the race. Your pace just has to be a bit more than half of his speed. his speed is 17mph. yours, by logic, needs to be even a tad bit more than 8.5mph. You need to have a faster speed than 8.5mph (8.51mph works perfectly) and you win by a hair. But when we se your example, you're only going at 7mph. A whole mile and a half behind pace. Sadly, he passes you short before winning.
The second example is YES he does pass you before the end of the trail.
<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helped</u></em><em><u>.</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>spent</u></em><em><u> </u></em><em><u>around</u></em><em><u> </u></em><em><u>20</u></em><em><u> </u></em><em><u>minutes</u></em><em><u> </u></em><em><u>writing</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>answer</u></em><em><u>,</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>5</u></em><em><u> </u></em><em><u>star</u></em><em><u>,</u></em><em><u> </u></em><em><u>like</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>noter</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>"</u></em><em><u>BRAINLIEST</u></em><em><u> </u></em><em><u>ANSWER"</u></em><em><u> </u></em><em><u>would</u></em><em><u> </u></em><em><u>be</u></em><em><u> </u></em><em><u>very</u></em><em><u> </u></em><em><u>much</u></em><em><u> </u></em><em><u>apreciated</u></em><em><u>!</u></em><em><u> </u></em><em><u>H</u></em><em><u>a</u></em><em><u>ve</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>good</u></em><em><u> </u></em><em><u>day</u></em><em><u>!</u></em><em><u>!</u></em>