Who can ask me a question about addition?

Consider the system x' = rx + x3 - x5, which exhibits a pitchfork bifurcation.

trapecia [35]

Answer:

rs = -3/16 and the three minima x₁, x ₂ and x₄ fall at the value of integrating curve C

Step-by-step explanation:

The answer is found in the attachment.

5 0

3 years ago

Find the distance between the pair of points and then round your answer to the nearest tenth.

Travka [436]

Answer:

$d = 9.4 units$ (nearest tenth)

Step-by-step explanation:

Given the distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ , distance between (-4, 5) and (4, 0) is calculated as follows:

Let $(-4, 5) = (x_1, y_1)$

$(4, 0) = (x_2, y_2)$

$d = \sqrt{(4 - (-4))^2 + (0 - 5)^2}$

$d = \sqrt{(8)^2 + (- 5)^2}$

$d = \sqrt{64 + 25}$

$d = \sqrt{89}$

$d = 9.4 units$ (nearest tenth)

3 0

3 years ago

A student finished a 30 question test in 75 minutes. Which rate best represents the relationship between the number of minutes s

blagie [28]

Answer:

2.5 minutes per quesiton

Step-by-step explanation:

75 minutes to take 30 quesitons means you divide the time equally so

75/30

5 0

3 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

so

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

so

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

What is the rate of change of y=-4/9x+5

WARRIOR [948]

Answer:

Rate of change of y is $- \frac{4}{9}$

Step-by-step explanation:

$y = - \frac{4}{9} x + 5 \\ \\ differentiating \: with \: respect \: to \: x \\ \\ \frac{dy}{dx} = - \frac{4}{9} \frac{d}{dx} x + \frac{d}{dx} 5 \\ \\ \frac{dy}{dx} = - \frac{4}{9} .1 + 0 \\ \\ \huge \red{\frac{dy}{dx} = - \frac{4}{9} } \\ \\ rate \: of \: change \: of \: y =- \frac{4}{9}$

8 0

2 years ago