Fnd the value of x................

Mathematics

1 answer:

lilavasa [31]2 years ago

4 0

So to solve a,
You already have the first two answers which are 65 and 90. Since a tríenle always has to equal 180 you just add 65 and 90 and the subtract that number by 180 and that’s your other missing angle.
Both triangles are identical so you just have to insert the answers from the right triangle onto the left triangle.
A is the only one that I knew how to solve, sorry

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Find x, round to the nearest tenth degree.

Romashka [77]

Answer:

Step-by-step explanation:

Use the Law of Cosines

A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°

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2 years ago

Use determinants to find out if the matrix is invertible.

wariber [46]

Answer:

The matrix is not invertible.

Step-by-step explanation:

We are given the following matrix in the question:

$A =\left[\begin{array}{ccc}-5&0&1\\-1&3&2\\0&10&6\end{array}\right]$

Condition for invertible matrix:

A matrix is invertible if and only if the the determinant is non-zero.

We can find the determinant of the matrix as:

$|A| = -5[(3)(6)-(2)(10)]-0[(-1)(6)-(2)(0)] + 1[(-1)(10)-(3)(0)]\\|A| = -5(18-20)+(-10)\\|A| = 10-10\\|A| = 0$

Since the determinant of the given matrix is zero, the given matrix is not invertible.

5 0

2 years ago

Pls pls help<br> Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

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<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.