Answer:
if x=-1 then its is NOT in the domain of h.
Step-by-step explanation:
Domain is the set of values for which the function is defined.
we are given the function
h(x) = x + 1 / x^2 + 2x + 1
h(x) = x+1 /x^2+x+x+1
h(x) = x+1/x(x+1)+1(x+1)
h(x) = x+1/(x+1)(x+1)
h(x) = x+1/(x+1)^2
So, the function h(x) is defined when x ≠ -1
Its is not defined when x=-1
So, if x=-1 then its is NOT in the domain of h.
You know if something is a function or not because the X will never be used twice in a set. If it is, then it's not a function.
A. Uses -1 twice
B. Uses Nothing twice (good)
C. Uses 0 twice
D. Uses 0 twice
B is your answer
Ken earns 54 dollars at his part-time job on Friday
Given that Total amount earned by ken and his wife at their part-time job on Friday= $174
Money earned by ken= x dollars
Money earned by ken's wife = (2x+12) dollars
Total amount earned by ken and his wife at their part-time job on Friday= x dollars + (2x+12) dollars
(x + 2x + 12 ) dollars = $ 174 ( addition of ken and ken's wife income and total amount earned by ken and his wife at their part-time job on Friday is $174)
(3x + 12 ) dollars = $ 174
3x=$162
x=
x= 54 dollars
Therefore,54 dollars were earned by ken at his part-time job on Friday
Hence,Ken earns 54 dollars at his part-time job on Friday
Learn more about dollars here:
brainly.com/question/14982791
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Answer: A or C (i think A because its not including)
Step-by-step explanation: