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3 years ago

What can you multiply by 1050 to get 21,000? Proportional Problem!

Mathematics

2 answers:

FinnZ [79.3K]3 years ago

5 0

Answer:

If you multiple 1050 by 20 you will get 21,000.

trapecia [35]3 years ago

3 0

If you multiply 1050 x 20 you should get 21,000

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Help! Is the binomial a factor of the polynomial function? f(x)=2x^3+15x^2+22x-15.

klasskru [66]

Answer:

yes, no, yes, no, no, yes

Step-by-step explanation:

Check if the zero of each binomial is a zero of the polynomial. If it is, then the binomial is a factor.

f(-3) = 0

f(3) = 240

f(-5) = 0

f(5) = 720

f(-1/2) = -22.5

f(1/2) = 0

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3 years ago

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Tìm x biết 1) 2x(x-8)+x-8=0 2) 2x^3-32x=0 3) 5x(x-2021)-x+2021=0

Keith_Richards [23]

Answer:

C) x – 2). 2 ... -2x ≤ 2. ⇔ x ≥ -1. Tập nghiệm S = {x | x ≥ -1}. Bài 2. Gọi x (km) là quãng đường

Step-by-step explanation:

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2 years ago

18 POINTS! At the AoPS office, mice vary inversely with cats, that is, mice=k/cats, for some value of k. When there are 3r-19 ca

Blizzard [7]

Answer:

k=30

Step-by-step explanation:

The number of mice vary inversely with cats. This is written as:

$Mice \propto \dfrac{1}{Cat} \\Mice = \dfrac{k}{Cat}$

When there are 3r-19 cats, there are 2r+1 mice

$2r+1 = \dfrac{k}{3r-19}\\$Cross multiply$\\k=(3r-19)(2r+1)$

When there are 6r-27 mice, there are r-5 cats.

$6r-27 = \dfrac{k}{r-5}\\$Cross multiply$\\k=(6r-27)(r-5)$

Taking the values of k above, we have:

$k=(3r-19)(2r+1) =(6r-27)(r-5)\\(3r-19)(2r+1) =(6r-27)(r-5)\\6r^2+3r-38r-19=6r^2-30r-27r+135\\$Collect like terms\\6r^2-6r^2+3r+30r-38r+27r-19-135=0\\22r-154=0\\22r=154\\$Divide both sides by 22\\r=7$

Therefore:

$k=(3r-19)(2r+1) \\=(3*7-19)(2*7+1)\\=(21-19)(14+1)\\=2*15\\k=30$

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3 years ago

A company is experimenting with two new boxes for packaging merchandise. Each box is a cube with the side lengths shown. (smalle

sergij07 [2.7K]

Answer:

2 : 3

Step-by-step explanation:

12 : 18 is the ratio, but we have to simplify. The GCF (greatest common factor) is 6, so let's divide them both by 6. Right now, we get

2 : 3

3 0

3 years ago

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Hi Help me with question 6b) pls

Romashka-Z-Leto [24]

Answer:

k = 9

Step-by-step explanation:

Consider the pattern on the right side , that is

$T_{k}$ = k(k + 2) + 1 = k² + 2k + 1

Equating

k² + 2k + 1 = 100 ( subtract 100 from both sides )

k² + 2k - 99 = 0 ← in standard form

(k + 11)(k - 9) = 0 ← in factored form

Equate each factor to zero and solve for k

k + 11 = 0 ⇒ k = - 11

k - 9 = 0 ⇒ k = 9

But k > 0 , then k = 9

5 0

2 years ago