idk how to help you sorry :(
Factor out the common term; 3
(3(x + 1))^2 = 36
Use the Multiplication Distributive Property; (xy)^a = x^ay^a
3^2(x + 1)^2 = 36
Simplify 3^2 to 9
9(x + 1)^2 = 36
Divide both sides by 9
(x + 1)^2 = 36/9
Simplify 36/9 to 4
(x + 1)^2 = 4
Take the square root of both sides
x + 1 = √4
Since 2 * 2 = 4, the square root of 2 is 2
x + 1 = 2
Break down the problem into these 2 equations
x + 1 = 2
x + 1 = -2
Solve the first equation; x + 1 = 2
x = 1
Solve the second equation; x + 1 = -2
x = -3
Collect all solutions;
<u>x = 1, -3</u>
Answer: Store C by far, less money more time.
Step-by-step explanation:
Associative property is only applied to addition and multiplication. Thus, it can't be applied to subtraction. This property is manifested when you get the same answer no matter where you put the parenthesis. Example of associative property is:
(50 + 2) + (92 + 6) = 52+98 = 150
50 + (2+92) + 6 = 50 + 94 + 6 = 150
Here is the counter example for the subtraction of decimals:
(3.45 - 8.92) - (1.9 - 7.3) = -5.47 - ⁻5.4 = -0.07
3.45 - (8.92 - 1.9) - 7.3 = 3.45 - 7.02 - 1.9 = -5.47
As you can see, the answers are not the same.
The user corrected that the scale of a drawing of a park reads: 5 miles to 1 cm , and we know that the park measures 1,600 square meters (user insisted that this measure is given in square meters and not square miles).
So we have to convert the 1600 square meters into miles, knowing that 1 meter is the same as: 0.000621371 miles
then meters square will be equivalents to:
1 m^2 = (0.000621371 mi)^2
then 1600 m^2 = 0.00061776 mi^2
now, since 5 miles are represented by 1 cm, then 25 square miles will be represented by 1 square cm
and therefore 0.00061776 square miles will be the equivalent to:
0.00061776 / 25 cm^2 = 0.000024710 cm^2
So and incredibly small number of square cm.
I still believe that some of the information you gave me are not in meters but in miles. (For example, the park may not be in square meters but in squared miles). The park seems to have the size of a house according to the info.