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Annette [7]
3 years ago
12

3) Slope = 4, passing through (-1,5) Slope

Mathematics
2 answers:
Nonamiya [84]3 years ago
7 0
Be more specific boo xxo
Tanzania [10]3 years ago
3 0
4x +y-21=o
explanation using point grade formula y
1
)
=
m
(
x
−
x
1
)

where
(
x
1
,
y
1
)
is
(
4
,
5
)
(
y
−
5
)
=
−
4
(
x
−
4
)

y
−
5
=
−
4
x
+
16

4
x
+
y
−
21
=
0
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PLease hurry! i need it! And the testing thing is happening, so before 6 pm?
ololo11 [35]

\begin{cases} -x+3y=9\\\\ y=\cfrac{2}{3}x \end{cases} \\\\[-0.35em] ~\dotfill\\\\ -x+3y=9\implies 3y=9+x\implies \underline{3y-9=x} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{substituting ont the 2nd equation}}{y=\cfrac{2}{3}(\underline{3y-9})\implies 3y=2(3y-9)}\implies 3y=6y-18\implies 18+3y=6y \\\\\\ 18=3y\implies \cfrac{18}{3}=y\implies \boxed{6=y}

8 0
3 years ago
The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
vagabundo [1.1K]

Answer: Area (upper bound) = 4527.7056 cm²

               Perimeter (lower bound) = 278 cm

<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

8 0
4 years ago
Read 2 more answers
nida is buying a small storage box online. She sees a cube box with volume of 125cm^3. What is the length of each box edge?
aleksklad [387]

Answer:

5 cm

Step-by-step explanation:

Here, we want to get the length of each box edge

Let the length be s

Mathematically, the volume of a cube is s^3

Thus;

s^3 = 125

s^3 = 5^3

s = 5 cm

5 0
3 years ago
Which statements are true about the graph of the function f(x) = x2 – 8x + 5? Check all that apply.
statuscvo [17]

Answer:

A, D, E are true

Step-by-step explanation:

You have to complete the square to prove A.  Do this by first setting the function equal to 0, then moving the 5 to the other side.

x^2-8x=-5

Now we can complete the square.  Take half the linear term, square it, and add it to both sides.  Our linear term is 8 (from the -8x).  Half of 8 is 4, and 4 squared is 16.  So we add 16 to both sides.

(x^2-8x+16)=-5+16

We will do the addition on the right, no big deal.  On the left, however, what we have done in the process of completing the square is to create a perfect square binomial, which gives us the h coordinate of the vertex.  We will rewrite with that perfect square on the left and the addition done on the right,

(x-4)^2=11

Now we will move the 11 back over, which gives us the k coordinate of the vertex.

(x-4)^2-11=y

From this you can see that A is correct.

Also we can see that the vertex of this parabola is (4, -11), which is why B is NOT correct.

The axis of symmetry is also found in the h value.  This is, by definition, a positive x-squared parabola (opens upwards), so its axis of symmetry will be an "x = " equation.  In the case of this type of parabola, that "x = " will always be equal to the h value.  So the axis of symmetry is

x = 4, which is why C is NOT correct, either.

We can find the y-intercept of the function by going back to the standard form of the parabola (NOT the vertex form we found by completing the square) and sub in a 0 for x.  When we do that, and then solve for y, we find that when x = 0, y = 5.  So the y-intercept is (0, 5).

From this you can see that D is also correct.

To determine if the parabola has real solutions (meaning it will go through the x-axis twice), you can plug it into the quadratic formula to find these values of x.  I just plugged the formula into my graphing calculator and graphed it to see that it did, indeed, go through the x-axis twice.  Just so you know, the values of x where the function go through are (.6833752, 0) and (7.3166248, 0).  That's why you need the quadratic formula to find these values.

7 0
4 years ago
Lj thank u so much for helping me
wlad13 [49]

- 8 / 20 = y / - 4

y = - 4 × - 8 / 20

y = 4 × 8 / 4 × 5

y = 8 / 5

6 0
3 years ago
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