Find the equation of a line that contains the points (6, -7) and (8,5). Write the equation in slope-intercept form.

Mathematics

1 answer:

Anna [14]3 years ago

6 0

Answer:

y = 6x - 43

Step-by-step explanation:

(6, -7) and (8,5)

m=(y2-y1)/(x2-x1)

m=(5 + 7)/(8 - 6)

m= 12/2

m = 6

y - y1 = m(x - x1)

y + 7 = 6(x - 6)

y + 7 = 6x - 36

y = 6x - 43

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What are the solutions of x^2 = -7x-8

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$Steps:$

$x^2=-7x-8$

$\mathrm{Add\:}8\mathrm{\:to\:both\:sides},\\x^2+8=-7x-8+8$

$\mathrm{Simplify},\\x^2+8=-7x$

$\mathrm{Add\:}7x\mathrm{\:to\:both\:sides},\\x^2+8+7x=-7x+7x$

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$Solve\:with\:the\:quadratic\:formula,\\\mathrm{For\:}\quad a=1,\:b=7,\:c=8:\quad x_{1,\:2}=\frac{-7\pm \sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1},\\x=\frac{-7+\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7+\sqrt{17}}{2},\\x=\frac{-7-\sqrt{7^2-4\cdot \:1\cdot \:8}}{2\cdot \:1}:\quad \frac{-7-\sqrt{17}}{2}$