Answer:
Step-by-step explanation:
The solid is a cuboid with length of 6 inches, a width of 3 inches, and a height of 2 inches.
The volume is l× w×h = 6×3×2 = 36inches^3
Therefore, the following statements are true about the Solid
1) The volume of the solid is 36 in.3.
2) The perimeter of one of its faces is 10 inches.(2width + 2 height = 2×2 + 2×3 = 10 inches)
3) The area of one of its faces is 6 inches^2. (width × height = 3×2 = 6 inches)
4) The area of one of its faces is 12 in.2.(length × height = 6×2 = 12 inches^2)
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
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Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
Answer:
The length of WX is 31 units.(third option)
Step-by-step explanation:
Given that In trapezoid WXYZ, WX║ZY and S and T are the mid points of the sides WZ and XY. We have to find the length of WX.
By trapezoid mid-segment Property,
A mid-segment of a trapezoid join the midpoints of the two non-parallel sides of trapezoid. The length of the mid-segment is the average of the lengths of the two bases and is parallel to the bases of the trapezoid.
∴ ![ST=\frac{WX+ZY}{2}](https://tex.z-dn.net/?f=ST%3D%5Cfrac%7BWX%2BZY%7D%7B2%7D)
⇒ ![48=\frac{WX+65}{2}](https://tex.z-dn.net/?f=48%3D%5Cfrac%7BWX%2B65%7D%7B2%7D)
⇒ ![96=WX+65](https://tex.z-dn.net/?f=96%3DWX%2B65)
⇒ ![WX=96-65=31](https://tex.z-dn.net/?f=WX%3D96-65%3D31)
The length of WX is 31 units.(third option)