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bija089 [108]
3 years ago
13

PLEASE I NEED HELP!!!!

Mathematics
1 answer:
Marianna [84]3 years ago
8 0

<u>Q.</u> Determine if the rates are equilvalent. Explain your reasoning. 25 hours in 5 days; 8 hours in 2 days. . .

\dashrightarrow No!, as, we have 25 hours in 5 dyas is the equals to 5. While, 8 hours in 2 days is equals to 4.

Here, is a difference of 1 in 5 and 4.

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Bro could i get some help
Paraphin [41]

Answer: wow that’s a lot of stuff

Step-by-step explanation:

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3 0
3 years ago
3y''-6y'+6y=e*x sexcx
Simora [160]
From the homogeneous part of the ODE, we can get two fundamental solutions. The characteristic equation is

3r^2-6r+6=0\iff r^2-2r+2=0

which has roots at r=1\pm i. This admits the two fundamental solutions

y_1=e^x\cos x
y_2=e^x\sin x

The particular solution is easiest to obtain via variation of parameters. We're looking for a solution of the form

y_p=u_1y_1+u_2y_2

where

u_1=-\displaystyle\frac13\int\frac{y_2e^x\sec x}{W(y_1,y_2)}\,\mathrm dx
u_2=\displaystyle\frac13\int\frac{y_1e^x\sec x}{W(y_1,y_2)}\,\mathrm dx

and W(y_1,y_2) is the Wronskian of the fundamental solutions. We have

W(e^x\cos x,e^x\sin x)=\begin{vmatrix}e^x\cos x&e^x\sin x\\e^x(\cos x-\sin x)&e^x(\cos x+\sin x)\end{vmatrix}=e^{2x}

and so

u_1=-\displaystyle\frac13\int\frac{e^{2x}\sin x\sec x}{e^{2x}}\,\mathrm dx=-\int\tan x\,\mathrm dx
u_1=\dfrac13\ln|\cos x|

u_2=\displaystyle\frac13\int\frac{e^{2x}\cos x\sec x}{e^{2x}}\,\mathrm dx=\int\mathrm dx
u_2=\dfrac13x

Therefore the particular solution is

y_p=\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x

so that the general solution to the ODE is

y=C_1e^x\cos x+C_2e^x\sin x+\dfrac13e^x\cos x\ln|\cos x|+\dfrac13xe^x\sin x
7 0
3 years ago
What is that product of 2x + y and 5x -y + 3
poizon [28]

Answer:

10x² + 6x + 3xy + 3y - y²

Step-by-step explanation:

Each term in the second factor is multiplied by each term in the first factor, as shown

(2x + y)(5x - y + 3)

= 2x(5x - y + 3) + y(5x - y + 3) ← distributing

= 10x² - 2xy + 6x + 5xy - y² + 3y ( collect like terms )

= 10x² + 6x + 3xy + 3y - y²


7 0
3 years ago
Read 2 more answers
In how many ways can 12 books be displayed on a shelf if the given number of books are available
Cerrena [4.2K]
The answer is not applicable. theres not enough information. -fvmousskaylaa
4 0
3 years ago
A line passes through the point (4, -6) and has a slope of 3/2 . Write an equation in slope-intercept form for this line.
tatyana61 [14]

A slope intercept form: y = mx + b where m = slope and b = y -intercept

A slope of 3/2 is given

So y = 3/2 x + b

To find b:

b = y - mx

A line passes through the point (4, -6)

b = -6 - (3/2)(4)

b = -6 - 6

b = - 12

Answer

Equation in  slope intercept form:  y = 3/2 x - 12


8 0
3 years ago
Read 2 more answers
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