Write a polynomial, f(x), with degree 5 that has zeros 1, √2, -√2, √3, -√3.
1 answer:
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Number of solutions: no roots
Type of solution: Not Real
Step-by-step explanation:
We need to identify the number of solutions and their types using the discriminant.
We are given:
Rearranging:
Discriminant can be found by:
where b=-40, a=10 and c=41
Putting values:
So, Discriminant is -40
If the discriminant is less than zero i.e -40 then there are no real roots.
So, Number of solutions: no roots
Type of solution: Not Real
Keywords: discriminant
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