What is the solution to the system of equations below?
{3x+4y=(-2)
{2x-4y=(-8)
2 answers:
Answer:
x = -2 , y = 1
Step-by-step explanation:
add the terms :
3x+2x+4y-4y = -2-8
5x = -10
x = -2
now that x = -2 , plug its value into any of the two equations (we'll take the first)
3*-2 +4y = -2
4y = 4
y = 1
Answer:
x = -2
y = 1
Step-by-step explanation:
{3x+4y=(-2)
{2x-4y=(-8)
{4y = -2 - 3x
{2x - 4y = -8
Substitute the value of 4y in 2x - 4y = -8
2x - (-2 - 3x) = -8
x= - 2
Substitute the value of x into 2x - 4y = -8
= 2x (-2) - 4y = -8
y = 1
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