x²-6x =7
First we have get rid of that 7 from the right side and move it to the left side. To move 7 to the left side, we have to subtract 7 from both sides.
x²-6x-7= 7-7
x²-6x-7 = 0
To make this equation a perfect square, first we have to check the x term. Here -6x given. We have to divide the co-efficient of x by 2, and then we have to add the square of it.
The co-efficient of x is -6 here. Dividing it by 2, we will get -6/2 = -3.
We will have to add (-3)² here. (-3)² is 9. So in the place of -7, we have to make 9, to make the equation a perfect square.
9-(-7) = 9+7 = 16
So by adding 16 to the left side, we can make the equation a perfect square.
x²-6x-7+16 =0
x²-6x+9 =0
x²-6x+(-3)² =0
(x-3)² =0
Complete Question:
Each night you total the day's sales and the total volume of ice cream sold in your shop. You notice that when an employee named Ben works, the mean price of the ice cream sold is $2.30 per pint with a standard deviation of $0.05. On nights when an employee named Jerry works, the mean price of the ice cream sold is $2.25 per pint with a standard deviation of $0.35. Which employee likely receives more complaints that his servings are too small? Explain.
Answer:
The employee that likely receives more complaints that his servings are too small is Jerry.
Step-by-step explanation:
a) Data:
Ben's mean price of ice cream sold = $2.30 per pint
Ben's mean price has a standard deviation = $0.05 (2.2%)
Jerry's mean price of ice cream sold = $2.25 per pint
Jerry's mean price has a standard deviation = $0.35 (15.5%)
b) Whereas the mean price of Ben's ice cream is $2.30, Jerry's mean price is less by $0.05, more than 20%. On the other hand, the standard deviation of Ben's mean price is $0.05 (about 2.2% variation), while Jerry's is $0.35 representing about 15.6% variation. This means that the variations in Jerry's price are far too much when compared to Ben's.
c) Percentages of Variations:
Ben = $0.05/$2.30 * 100 = 2.2%
Jerry = $0.35/$2.25 * 100 = 15.6%
Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
