Given that ABCD is a rhombus, what is the value of x?
1 answer:
Answer:
x is 29
Step-by-step explanation:
In a rhombus diagonals bisect perpendicularly.
let the centre point of the rhombus be O.
By seeing the diagram we can say that Angle DBC is congruent to angle ADB.
We can say they are congruent because they are symmetric about the diagonals and also by the principle of parallel lines.
Also ADB is a right angled triangle so ,
Hence the value of x is 29.
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Answer: The calculations are done below.
Step-by-step explanation:
(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,
Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.
(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,
Since, BC = CA, so the triangle ABC will be an isosceles triangle.
(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,
Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.
(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,
Since AB² + CA² = BC², so this will be a right angled triangle.
(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,
Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.
Thus, the match is done.