Answer:
P(inside larger square and outside smaller) = 
Step-by-step explanation:
Probability is the result of the division of the number of possible outcome by the number of an event.
In the question, for a point chosen, the point can be in the small square only or in the area or region between the small square and the big square as such,
Area of larger square = area of region between both squares + area of smaller square
Where the area of a square is S × S where S is the side of a square
Area of larger square = 10 × 10
= 100 cm square
Area of smaller square = 7 × 7
= 49 cm square
Area of the region between both squares
= 100 - 49
= 51 cm square
The probability that a dot selected is inside the larger square and outside the smaller is
P(inside larger square and outside smaller) = Area of region between both square/ Area of larger square
P(inside larger square and outside smaller) =
Answer:
Your answer is: (a little big) ----> 1175/819
Mixed number form: 1 356/819
Combine the fractions by finding a common denominator.
Step-by-step explanation:
Hope this helped : )
Answer:
$11.00
Explanation:
$60 given - $49 order = $11 change
Your question can be quite confusing, but I think the gist of the question when paraphrased is: P<span>rove that the perpendiculars drawn from any point within the angle are equal if it lies on the angle bisector?
Please refer to the picture attached as a guide you through the steps of the proofs. First. construct any angle like </span>∠ABC. Next, construct an angle bisector. This is the line segment that starts from the vertex of an angle, and extends outwards such that it divides the angle into two equal parts. That would be line segment AD. Now, construct perpendicular line from the end of the angle bisector to the two other arms of the angle. This lines should form a right angle as denoted by the squares which means 90° angles. As you can see, you formed two triangles: ΔABD and ΔADC. They have congruent angles α and β as formed by the angle bisector. Then, the two right angles are also congruent. The common side AD is also congruent with respect to each of the triangles. Therefore, by Angle-Angle-Side or AAS postulate, the two triangles are congruent. That means that perpendiculars drawn from any point within the angle are equal when it lies on the angle bisector
