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RUDIKE [14]
2 years ago
9

PLZ HELP! NO FAKE ANSWER PLEASE!!!!!! PLEASE AND THANK YOU MARRY CHRISTMAS!

Mathematics
2 answers:
lilavasa [31]2 years ago
8 0

Answer:

1. m=1/2

2. x=4/7

3. t=4

4. y=5

Step-by-step explanation:

1. 5m+4=7m+6

5m-7m=6-5

2m=1

m=1/2

2. -5x+3=2x-1

-5x-2x=-1-3

-7x=-4

x= -4/-7= 4/7

3. 5t-3=3t+5

5t-3t=5+3

2t=8

t=8/2= 4

4. 53y-55= 42y

53y-42y=55

11y=55

y=55/11=5

hope it helps!

andrew-mc [135]2 years ago
3 0

Answer:

1. 5m+4=7m+6

Step 1: Subtract 7m from both sides.

5m+4−7m=7m+6−7m

−2m+4=6

Step 2: Subtract 4 from both sides.

−2m+4−4=6−4

−2m=2

Step 3: Divide both sides by -2.

\frac{-2m}{-2}  = \frac{-2}{2}

m=−1

_______________________________

2.  −5x+3=2x−1

Subtract 2x from both sides.

−5x+3−2x=−1

Combine −5x and −2x to get −7x.

−7x+3=−1

Subtract 3 from both sides.

−7x=−1−3

Subtract 3 from −1 to get −4.

−7x=−4

Divide both sides by −7.

x= \frac{-4}{-7}

Faction \frac{-4}{-7} can be simplified to \frac{4}{7} by removing the negative sign from both the numerator and the denominator.

x= \frac{4}{7}

_____________________________

3. 5t−3=3t+5

Subtract 3t from both sides.

5t−3−3t=5

Combine 5t and −3t to get 2t.

2t−3=5

Add 3 to both sides.

2t=5+3

Add 5 and 3 to get 8.

2t=8

Divide both sides by 2.

t= \frac{8}{2}

Divide 8 by 2 to get 4.

t= 4

___________________________

4. 3y−55=42y

Subtract 42y from both sides.

53y−55−42y=0

Combine 53y and −42y to get 11y.

11y−55=0

Add 55 to both sides. Anything plus zero gives itself.

11y=55

Divide both sides by 11

y= \frac{55}{11}

Divide 55 by 11 to get 5.

y=5

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A binomial distribution has p = 0.05 and n = 50. what is the mean of this distribution?
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2.5 is the mean of this distribution.

What is the distribution's mean?

  • The expected value, commonly known as the mean of a statistical distribution with a continuous random variable, is calculated by integrating the product of the variable's probability as described by the distribution.
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Given: p = 0.05 and n= 50

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Therefore, option a is the correct answer. Other options are incorrect because these are irrelevant.

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7 0
1 year ago
A total of 754 tickets were sold for the school play. They were either adult tickets or student tickets. There were 54 more tick
Veseljchak [2.6K]

Answer:

Answer: 350

Step-by-step explanation:

Explanation:

a = adult tickets

s = student tickets

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║s = a + 54

Plug s = a + 54 into a + s = 754

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