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frosja888 [35]
3 years ago
13

Black is cutting a piece of rope into fourths. If each piece is 16 inches long, what is the length of the entire rope?

Mathematics
1 answer:
inessss [21]3 years ago
8 0
The answer is 64.....
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Which of the following describes the roots of the polynomial function f(x) = (x-3)^4(x+6)^2
erma4kov [3.2K]

write out every grouping

(x-3)(x-3)(x-3)(x-3)*(x+6)(x+6)

and multiply

4x^2+3x+63

5 0
3 years ago
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Below are two parallel lines with a third line intersecting them. What is x
sleet_krkn [62]

Answer:

136=x

Step-by-step explanation:

When an angle is shown, the one opposite of it is equal to the forst equation. The bottom angles are equal to 360ñ so if you take 46x2=92. Subtract 92 by 360 to get 268. Divide it by 2 to get one of the bigger angles, which is 134 degrees. And as for the top, one angle on the bottom is equal to the same spot on the top. so, 136=x

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3 years ago
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One day you bike for 30 miles 10 cool down at a rate of 0.25 miles/minute. The total distance you bike is 35 miles. How many min
tatyana61 [14]
To determine the length of time it would took for the biker to cool down, we need the rate that would relate the distance he traveled to cool down per units of time. For this problem, the rate is given as 0.25 miles per minute. So, we simply divide the total distance he traveled with this rate. We calculate as follows:

time to cool down = distance / rate
time to cool down = 35 miles / 0.25 miles / minute
time to cool down = 140 minutes or 2 hrs and 20 minutes

Therefore, the biker would need to cool down for about 2 hrs and 20 minutes if he traveled for 35 miles.
8 0
3 years ago
If m 180<br> °<br> then <br> A. <br> Obtuse<br><br> B. <br> Vertical<br><br> C. <br> Complementary<br><br> D. <br> Supplementary
insens350 [35]

Answer:

vertical

Step-by-step explanation:

because 180degrees is a straight line

6 0
3 years ago
Find the Area of the Shaded Region.
agasfer [191]

Answer:

I think it should be 32

Step-by-step explanation:

11 x 7= 77

9 x 5=45

77-45=32

3 0
3 years ago
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