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stira [4]
2 years ago
7

Ayrıntılı bir şekilde çözümü yazarmısınız ​

Mathematics
1 answer:
exis [7]2 years ago
4 0

Answer:

asi ñao lub ni huliao

Step-by-step explanation:

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(awarding brainliest) i’m not that smart pls help.
Alenkasestr [34]

Answer:

4) (2)(4)(3.14) = 25.12 m

5) (12)(3.14) = 37.68 ft

6) (2)(2)(3.14) = 12.56 yd

3 0
2 years ago
Can you verify my answer?<br><br> I believe it's reflection.
Anna007 [38]
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4 0
3 years ago
Which of the following are statistical questions? Select all that apply.
Olegator [25]
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5 0
2 years ago
on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solv
Cloud [144]
Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is <span>7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


</span>
8 0
3 years ago
Can someone please help me, Thanks - Alyssa T.
Oxana [17]
A=LW
192=(13+x)((9+x)
192=117+22x+x^2 (subtract 192 from both sides)
x^2+22x-75+0 (factor)
(x+25)(x-3)=0
so x=-25 or 3
Check work
since we are adding x it can only be the positive solution so x=3 so the new dimensions are:
L=13+3=16m
W=9+3=12
check: 16*12=192 so the answer is correct hope this helped
7 0
3 years ago
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