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Annette [7]
2 years ago
13

What are the square number factors of 56?​

Mathematics
1 answer:
balandron [24]2 years ago
7 0

Answer:

2,4,7,8,14,and 28

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At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist headi
gizmo_the_mogwai [7]
----------------------------------------------------------------------------------------------
Find the duration
----------------------------------------------------------------------------------------------
Time : 9:00am to 10:15am 
Duration: 1hour 15 mins or 1.25hours

----------------------------------------------------------------------------------------------
Find difference in distance travelled between the two cyclists.
----------------------------------------------------------------------------------------------
Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km

----------------------------------------------------------------------------------------------
Find the distance the cyclist traveled
----------------------------------------------------------------------------------------------
42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km

The slower cyclist traveled 17.5 km in the 1.25 hours

17.5 + 7.5 = 25 km

The faster cyclist traveled 25km in the 1.25 hours

----------------------------------------------------------------------------------------------
Find the speed of the slower cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km

The cyclist was traveling at 14km/h

----------------------------------------------------------------------------------------------
Find the speed of the faster cyclist
----------------------------------------------------------------------------------------------
1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km

The cyclist was traveling at 20km/hour

----------------------------------------------------------------------------------------------
Answer: The speed were 14km/h and 20 km/h
----------------------------------------------------------------------------------------------

8 0
4 years ago
Read 2 more answers
Ship collisions in the Houston Ship Channel are rare. Suppose the number of collisions are Poisson distributed, with a mean of 1
alexandr1967 [171]

Answer:

a) \simeq 0.3012   b) \simeq 0.0494 c) \simeq 0.2438

Step-by-step explanation:

Rate of collision,

1.2 collisions every 4 months

or, \frac{1.2}{4}

= 0.3 collisions per  month

So, the Poisson distribution for the random variable no. of collisions per month (X) is given by,

          P(X =x) = \frac{e^{-\lambda}\times {\lambda}^{x}}}{x!}


                                                           for x ∈ N ∪ {0}

                       =  0 otherwise --------------------------------------(1)

here, \lambda = 0.3 collision / month

No collision over a 4 month period means no collision per month or X =0

Putting X = 0 in (1) we get,

         P(X = 0) = \frac{e^{-0.3}\times {\0.3}^{0}}{0!}


                      \simeq 0.7408182207 ------------------------------------(2)

Now, since we are calculating  this for 4 months,

so, P(No collision in 4 month period)

     =0.7408182207^{4}

     \simeq 0.3012  -----------------------------------------------------------(3)

2 collision in 2 month period means 1 collision per month or X =1

Putting X =1 in (1) we get,

           P(X =1) = \frac{e^{-0.3}\times {\0.3}^{1}}{1!}


                      \simeq 0.2222454662 ------------------------------------(4)

Now, since we are calculating this for 2 months, so ,

P(2 collisions in 2 month period)

                =0.2222454662^{2}

                \simeq 0.0494 -----------------------------------------(5)

1 collision in 6 months period means

                                \frac{1}{6} collision per month

Now, P(1 collision in 6 months period)

= P( X = 1/6]  (which is to be estimated)

=\frac {P(X=0)\times 5 + P(X =1)\times 1}{6}

= \frac {0.7408182207 \times 5 + 0.2222454662 \times 1}{6}[/tex]

\simeq 0.6543894283-------------------------------------------(6)

So,

P(1  collision in 6 month period)

  =  0.6543894283^{6}

   \simeq 0.0785267444 ------------------------------------------------(7)

So,

P(No collision in 6 months period)

  = (P(X =0)^{6}

   \simeq 0.1652988882 ---------------------------------(8)

so,

P(1 or fewer collision in 6 months period)

= (8) + (7 ) = 0.0785267444 +0.1652988882

\simeq  0.2438 ---------------------------------------------(9)          

7 0
3 years ago
Heeeeeeeeeeeeeelllllllllllllppppppppppp
Temka [501]

Answer:

1/6*6

Step-by-step explanation:

3 0
4 years ago
The perimeter of a stop sign is 99.2 inches. Each side of the stop sign is equal.
san4es73 [151]

Answer: The equation can be written as 8n = 99.2.

Step-by-step explanation:

In my answer, I used the variable n to distinguish itself as one side of the stop sign. 99.2 is the final perimeter in inches.

A stop sign is an octagonal shape (otherwise, it is made up of 8 equal sides). Therefore, with this information, you can interpret that the length of one side would be equal to the length of all of the other sides.

Hence, the answer can be represented as 8n = 99.2.

6 0
3 years ago
Pic is question vuygvcutyfvgt
Furkat [3]

Answer:

30

Step-by-step explanation:

270/9 = 30

Hope This Helps & Good Luck :)

5 0
3 years ago
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