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Arturiano [62]
3 years ago
9

Please help with this problem. (both attachments are part of the same question)

Mathematics
1 answer:
liubo4ka [24]3 years ago
5 0

Answer:

C

Step-by-step explanation:

We are dining the value that is $92 fewer or less than she did on the 7th. On the 7th, she had $48. Subtracting $92, we get $48 - $98 = -$44 = money she had on the 14th. Therefore, the answer is C.

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Over a two hour time period a snail moved <br> 46<br> inches. How far is this in yards?
STALIN [3.7K]
1 inch = 0.0277778 1 * 46 = 46 0.0277778 x 46 = 1.27778 46 inches = 1.27778
4 0
3 years ago
If a pound of coffee costs $6, how many ounces can be bought for $3
saveliy_v [14]

8

Because 16 ounces is a pound half of 16 is 8, 8 ounces is half a pound. :)

8 0
4 years ago
Read 2 more answers
[6+4=10 points] Problem 2. Suppose that there are k people in a party with the following PMF: • k = 5 with probability 1 4 • k =
kirza4 [7]

Answer:

1). 0.903547

2). 0.275617

Step-by-step explanation:

It is given :

K people in a party with the following :

i). k = 5 with the probability of $\frac{1}{4}$

ii). k = 10 with the probability of $\frac{1}{4}$

iii). k = 10 with the probability $\frac{1}{2}$

So the probability of at least two person out of the 'n' born people in same month is  = 1 - P (none of the n born in the same month)

= 1 - P (choosing the n different months out of 365 days) = 1-\frac{_{n}^{12}\textrm{P}}{12^2}

1). Hence P(at least 2 born in the same month)=P(k=5 and at least 2 born in the same month)+P(k=10 and at least 2 born in the same month)+P(k=15 and at least 2 born in the same month)

= \frac{1}{4}\times (1-\frac{_{5}^{12}\textrm{P}}{12^5})+\frac{1}{4}\times (1-\frac{_{10}^{12}\textrm{P}}{12^{10}})+\frac{1}{2}\times (1-\frac{_{15}^{12}\textrm{P}}{12^{15}})

= 0.25 \times 0.618056 + 0.25 \times 0.996132 + 0.5 \times 1

= 0.903547

2).P( k = 10|at least 2 share their birthday in same month)

=P(k=10 and at least 2 born in the same month)/P(at least 2 share their birthday in same month)

= $0.25 \times \frac{0.996132}{0.903547}$

= 0.0.275617

6 0
3 years ago
Math question down below
sergiy2304 [10]
I think the answer is 17.5 years

6 0
3 years ago
A survey found that 3 out of 100 randomly selected people have red hair. How many people in a group of 12,000 randomly selected
kirza4 [7]

Answer:

360 people out of 1200 are likely to have red hair.

Step-by-step explanation:

So I just saw that 100 x 120 equals 1200. So I just need to multiply 3 x 120 and I got 360. I think this is how to solve?

4 0
2 years ago
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