Step-by-step explanation:
Hey there!
The equation of a line which passes through the point (1,1) is <em>(y-1) = m1 (x-1)...............(i)</em> {using one point formula}
Also, another equation which is perpendicular to the line is <em>y = 1/5 x + 4/5..........(ii)</em>
Comparing equation (ii) with y= mx+c, we get;
Slope (m2) = 1/5.
Now, As per the condition of perpendicular lines,
m1*m2 = -1
or, m1 * 1/2 = -1
or, m1= -2
Therefore, m1 = -2.
Keeping the value of m1 in equation (i) we get;
y-1 = -2(x-1)
y-1 = -2x+1
or, y+2x-2= 0
Therefore, the required equation is 2x+y-2= 0.
Hope it helps!
Answer: p+p^2
Step-by-step explanation: shown in the attachment
Answer:
Can you elaborate, please?
Step-by-step explanation:
