Answer:
One hundred and fifty 40 pounds boxes and twenty 75 pounds boxes
Step-by-step explaination:
The maximum amount he can haul in one load is 7500 pounds
150 × 40 pounds boxes = 6000 pounds
20 × 75 pounds boxes = 1500 pounds
6000 pounds + 1500 pounds = 7500 pounds
Answer:
54
Step-by-step explanation:
Answer:
27.3 dollars
Step-by-step explanation:
Answer:
The claim that the scores of UT students are less than the US average is wrong
Step-by-step explanation:
Given : Sample size = 64
Standard deviation = 112
Mean = 505
Average score = 477
To Find : Test the claim that the scores of UT students are less than the US average at the 0.05 level of significance.
Solution:
Sample size = 64
n > 30
So we will use z test

Formula : 


Refer the z table for p value
p value = 0.9772
α=0.05
p value > α
So, we accept the null hypothesis
Hence The claim that the scores of UT students are less than the US average is wrong
Answer:
The answer is 3/1 or 3
Step-by-step explanation:
30/10 = 3/1 = 3
Thus, The answer is 3/1 or 3
<u>-TheUnknownScientist</u><u> 72</u>