Answer:
Explanation:
This is a typical problem of conditional probability.
In this case you know:
- the probability of the event D <em>(an international flight leaving the U.S. is delayed in departing</em>), which is 0.36 and you can write as P(D) = 0.36
- the probability of event P <em>(an international flight leaving the U.S. is a transpacific flight</em>), which is 0.25 and you can write as P(P) = 0.25;
- the joint probability of event P and D (<em>international flight leaving the U.S. is a transpacific and is delayed in departing</em>), which is 0.09 and you can write as P (P ∩ D) = 0.09.
You need to determine the <em>probability that an international flight leaving the United States is delayed given that the flight is a transpacific flight</em>, i.e. the conditional probability P (D/P).
Hence, use the formula for conditional probability:
- P (D/P) = P (D ∩ P) / P(D) = P (P ∩ D) / P (D)
- P (D/P) = 0.09 / 0.25 = 0.36
Answer:
The probability that the stock will sell for $85 or less in a year's time is 0.10.
Step-by-step explanation:
Let <em>X</em> = stock's price during the next year.
The random variable <em>X</em> follows a normal distribution with mean, <em>μ</em> = $100 + $10 = $110 and standard deviation, <em>σ</em> = $20.
To compute the probability of a normally distributed random variable we first need to compute the <em>z</em>-score for the given value of the random variable.
The formula to compute the <em>z</em>-score is:
Compute the probability that the stock will sell for $85 or less in a year's time as follows:
Apply continuity correction:
P (X ≤ 85) = P (X < 85 - 0.50)
= P (X < 84.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that the stock will sell for $85 or less in a year's time is 0.10.
The answer will be 138.16
You will find the answer by multiplying by 2 and 22 which will give you 44, then you multiply that but 3.14 which will give you 138.16
Answer:
0.8
Step-by-step explanation:
We can solve P(A or B) by using the following:
Since we know P(A) = 0.6, P(B) = 0.3 and P(A and B) = 0.1 we obtain:
