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Butoxors [25]
3 years ago
15

The following frequency table shows the number of Jui's pictures that have been published in each of the local

Mathematics
1 answer:
MrRa [10]3 years ago
3 0

Answer:2

2Step-by-step explanation:

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Find the volume of a cylinder with a diameter of 10 inches and height of 20in
weqwewe [10]

Answer:

V = 500 pi in^3

or approximately 1570 in ^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h  where r is  the radius and h is the height

The diameter is 10. so the radius is d/2 = 10/2 =5

V = pi (5)^2 * 20

V = pi *25*20

V = 500 pi in^3

We can approximate pi by 3.14

V = 3.14 * 500

V = 1570 in ^3

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3 years ago
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Someone help and plz make sure it’s right :)
fenix001 [56]
The value of the trigonometric ratio, Cos C is 5/13. The answer is A.
3 0
3 years ago
Please help with 24-26
Inga [223]

24

The power 0 only affects the x. x^0 = 1

-2 * 1 = -2

25

Here everything inside the brackets is affected by the 0.

(11abx)^0 = 1 There is nothing left over.

26

(xy)^0 = 1

(pq)^0 = 1

1 - 1 = 0


3 0
3 years ago
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A pond has 150 fish and the population decreases by 8% each day. How many days before there are 30 fish
nlexa [21]

Answer:

19 days

Step-by-step explanation:

Given

a = 150 --- initial

r = 8\% -- rate

Required

Days when the fish gets to 30

The function is exponential and as such it follows;

y = ab^x

Where x represents the number of days and y the number of fishes

Because the fishes decreases;

b = 1 - r

So, we have:

b = 1 - 8\%

Express as decimal

b = 1 - 0.08

b = 0.92

In y = ab^x

a =150

y = 30

b = 0.92

So, we have:

30 = 150 * 0.92^x

Divide both sides by 150

0.2 = 0.92^x

Take log of both sides

log(0.2) = log(0.92^x)

Apply law of logarithm

log(0.2) = x\ log(0.92)

Make x the subject

x = \frac{log(0.2)}{log(0.92)}

x = \frac{-0.6990}{-0.0362}

x = 19.309

x \approx 19

<em>Hence, it takes approximately 19 days</em>

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3 years ago
What rational numbers can be expressed as terminating decimals?
mafiozo [28]
The answer is B) 3/5
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3 years ago
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