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3 years ago

The points (s,9) and (0, - 1) fall on a line with an undefined slope. what is the value of s?

Mathematics

1 answer:

blsea [12.9K]3 years ago

5 0

Undefined slope is a vertical line so s = 0.

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Write in its simplest form, the ratio 3.5kilograms:800grams

MA_775_DIABLO [31]

3.5 kg:800g
3500g:800g
35g:8g

4 0

3 years ago

HELP, PLATO!!!!!!!

Keith_Richards [23]

Answer:

the law of cosines with ABC

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2 years ago

A triangular pyramid and its net are shown. Rain uses Calculations below to conclude that the surface area of a triangular pyram

Harman [31]

Answer:

Rain is correct, calculates correctly, 238.5 square inches

Step-by-step explanation:

The given triangular pyramid is shown with the dimensions.

The surface area of the triangular pyramid is given by :

$A=\frac{1}{2}\left(a \times b\right) + 3\left(\frac{1}{2}\times b\times s\right)$

$A=\frac{1}{2}\left(10 \times 8.7\right) + 3\left(\frac{1}{2}\times 10\times 13\right)$

$A=43.5+(3\times 65)$

$A=43.5+195$

$A=238.5 \ \text{inche}^2$

Therefore, the surface area of the triangular pyramid is = 238.5 square inches.

5 0

3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 436.0 gram setting. It

Vilka [71]

Answer:

We conclude that the machine is under filling the bags.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 436.0 gram

Sample mean, $\bar{x}$ = 429.0 grams

Sample size, n = 40

Alpha, α = 0.05

Population standard deviation, σ = 23.0 grams

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 436.0\text{ grams}\\H_A: \mu < 436.0\text{ grams}$

We use one-tailed(left) z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{429 - 436}{\frac{23}{\sqrt{40}} } = -1.92$

Now, $z_{critical} \text{ at 0.05 level of significance } = -1.64$

Since,

$z_{stat} < z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that the machine is under filling the bags.

8 0

3 years ago

If the if a cylinder is 7 in tall and has a volume of 63 Pi inches what is the area of the cross section it goes right down the

vitfil [10]

Answer: $9\pi \ in.^2$

Step-by-step explanation:

Given

The height of the cylinder is $h=7\ in.$

The volume of the cylinder is $V=63\pi \ in.^3$

The volume of the cylinder is the product of area and height

$\Rightarrow V=\pi r^2h\\$

Insert the values

$\Rightarrow 63\pi =A\times 7\\\\\Rightarrow A=\dfrac{63\pi}{7}\\\\\Rightarrow A=9\pi\ in.^2$

Thus, the area of the cross-section is $9\pi \ in.^2$

7 0

3 years ago