Answer:
20
Step-by-step explanation:
For the sake of the problem, let's make female workers "x" and male workers "y".
x+y<40 This equation shows that the total number of workers has a max of 40.
30x+20y<1,000 This equation shows that the total cost the manager pays ($30 to each woman, $20 to each man) has a max of $1,000.
Now you can solve for x and y.
X+y<40
-y -y
X<-y+40
Substitute -y+40 in for X in the second equation
30(-y+40)+20y<1,000
-30y+1200+20y<1,000 Distribute
-10y+1,200<1,000 Combine like terms
-10y<-200 Subtract 1,200
y>20 Divide by -10; flip the sign
Since y>20, and y=male workers, you now know that the minimum
number of male workers he should send is 20
Answer:
The weight of large and small box are 18.25 kg and 13.25 kg respectively.
Step-by-step explanation:
Let the weight of large and small box are x and y respectively.
It is given that a delivery of 5 large boxes and 3 small boxes has a total weight of 131 kilograms.
.... (1)
A delivery of 2 large boxes and 6 small boxes has a total weight of 116 kilograms.
.... (2)
On solving (1) and (2) using graphing calculator, we get
Therefore the weight of large and small box are 18.25 kg and 13.25 kg respectively.
Answer:
<h2>C. <em>
20,160</em></h2>
Step-by-step explanation:
This question bothers on permutation since we are to select a some people out of a group of people and then arrange in a straight line. If r object are to be arranged in a straight line when selecting them from n pool of objects. This can be done in nPr number of ways.
nPr = n!/(n-r)!
Selection of 6 people out of 8 people can therefore be done in 8C6 number of ways.
8P6 = 8!/(8-6)!
8P6 = 8!/2!
8P6 = 8*7*6*5*4*3*2!/2!
8P6 = 8*7*6*5*4*3
8P6 = 56*360
8P6 = 20,160
<em>Hence this can be done in 20,160 number of ways</em>
Quantify of sand in a bag =
Quantity of sand that escapes in every 10 minutes :-
Quantity of sand that will escape in 20 minutes :-
Quantity of sand that will remain in the sand bag :-
