Answer:
Explanation:
The sickle cell allele is recessive. Hence, in order for any child of the couple to have sickle cell anemia, such a child will have to inherit an affected allele each from the two parents. This means that both the father and the mother must have affected alleles in their genotypes. In other words, two sickle cell alleles are required for the abnormality to manifest.
Let us assume that the sickle cell allele is represented by S and the normal allele is represented by A.
Now, it is established that the mother has sickle cell anemia, her genotype would be SS. The father does not have sickle cell, his genotype can either be AA or AS.
Assuming the genotype of the father is AA:
SS x AA
AS AS AS AS
<em>All the children would be normal in this case.</em>
Assuming that the genotype of the father is AS
SS x AS
AS SS AS SS
<em>50% of the children would have sickle cell while the remaining 50% would be normal.</em>
<u>Therefore, in order to produce children with sickle cell, the father has to be AS, otherwise, he has to be AA.</u>
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Answer: The genotype of the generation resulting from the given P ( parental generation) is Aa that is all offsprings in the first generation will be heterozygous dominant.
The genotype of the parents is AA and aa and the gametes produced by these parents are A and a respectively.
When these gametes fuse, they result in the offsprings with genotype Aa. This represents a dominant phenotype due to the presence of dominant gene ( a gene that masks the expression of recessive gene and expresses itself), which is A in this case.
When the sun is above the horizon and when the sun is below the horizon it is winter
Answer:
A dominant allele is denoted by a capital letter (A versus a).Since each parent provides one allele, the possible combinations are: AA, Aa, and aa. Offspring whose genotype is either AA or Aa will have the dominant trait expressed phenotypically, while aa individuals express the recessive trait.
