2/9 is less than 2/5 because since the denominator is larger, the pieces are smaller. (Numerator)
Answer:
<em>Answer is</em><em> </em><em>imaginary</em><em> </em><em>root</em><em>s</em>
Step-by-step explanation:
On solving the above mentioned equation we get some imaginary values.
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Answer:
12.
Step-by-step explanation:
Substitute this equation with a=3 and b=24:
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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Answer:
1/0.04 = 25
Step-by-step explanation:
