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Alenkinab [10]
2 years ago
6

What is the answer to 72/80 - 13/20

Mathematics
1 answer:
LenKa [72]2 years ago
4 0

Answer:

\frac{1}{4}

Step-by-step explanation:

\frac{72}{80} = \frac{18}{20}

so, \frac{18}{20} - \frac{13}{20} = \frac{18-13}{20} = \frac{5}{20}

\frac{5}{20} = \frac{1}{4}

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1. Trig Function
Dima020 [189]

The values of the given trig functions in terms of sinθ and/or cosθ are:

sinθ = <u>tanθ.cosθ</u>

cosθ = <u>sinθ/tanθ</u>

secθ = <u>1/cosθ</u>

cscθ = <u>1/sinθ</u>

tanθ = <u>sinθ/cosθ</u>

cotθ = <u>cosθ/sinθ</u>

<h3>Trigonometric functions </h3>

From the question, we are to determine the values of the given trig functions in terms of sinθ and/or cosθ

  • sinθ

NOTE: tanθ = sinθ / cosθ

∴ sinθ = tanθ.cosθ

  • cosθ

From above, we can write that

cosθ = sinθ/tanθ

  • secθ

Secant is the <u>inverse</u> of cosine

∴ secθ = 1/cosθ

  • cscθ (cosecθ)

Cosecant is the <u>inverse</u> of sine

∴ cscθ = 1/sinθ

  • tanθ

tanθ = sinθ/cosθ

  • cotθ

Cotangent is the <u>inverse</u> of tangent
∴ cotθ = 1/tanθ

But, tanθ = sinθ/cosθ

∴ cotθ = cosθ/sinθ

Hence, the values of the given trig functions in terms of sinθ and/or cosθ are:

sinθ = <u>tanθ.cosθ</u>

cosθ = <u>sinθ/tanθ</u>

secθ = <u>1/cosθ</u>

cscθ = <u>1/sinθ</u>

tanθ = <u>sinθ/cosθ</u>

cotθ = <u>cosθ/sinθ</u>

Learn more on Trigonometric functions here: brainly.com/question/10316891

#SPJ1

4 0
1 year ago
What is the value of the 35th term in the sequence -15, -11, -7, ...? 121 125 151 374
Andreas93 [3]

Answer:

121

Step-by-step explanation:

This is an arithmetic sequence.

First term  a = -15

Common difference [d] = second term - first term

                                  = -11 - [-15] = -11 + 15 = 4

nth term = a + (n-1) * d

35th term = -15 + (35 - 1) * 4

                = -15 + 34 * 4

                = - 15 + 136

                = 121

8 0
3 years ago
Read 2 more answers
Can someone help me answer this question please?
Mrrafil [7]
Fourth option has the same y-intercept of (0,3) as the sample above.
y+3=6x
it equals to y=6x-3
4 0
2 years ago
Read 2 more answers
Jeb is the local tennis pro at the country club, and he needs to know at what height the tennis ball needs to be when he hits it
suter [353]

Answer:

The height from ground, at which Jeb needs to hit the ball is 7.8 meters

Step-by-step explanation:

The given parameters are;

The distance away the tennis ball is hit = 20 meters;

The height of the tennis net = 0.3 m

The distance from the net the ball lands = 4 meters

The time the ball takes to land from the 0.3 m net height is given as follows;

t = √(h/(1/2×g)) = √(0.3/(1/2 × 9.8)) ≈ 0.2474

t ≈ 0.2474 seconds

The speed of the ball = Distance/Time = 4/0.2474 ≈ 16.166

The speed of the ball ≈ 16.166 m/s

The time it takes the ball to reach the net = 20/16.166 ≈ 1.24

The time it takes the ball to reach the net, tₓ ≈ 1.24 seconds

The height, hₓ the ball falls in 1.24 seconds is given as follows;

hₓ = 1/2·g·tₓ² = 1/2 × 9.8 × 1.24² = 7.5

The height, hₓ the ball falls in 1.24 seconds = 7.5 m

The height the ball falls in the time taken to reach the net from 20 meters = The height, hₓ the ball falls in 1.24 seconds

Therefore, the height at which Jeb needs to hit the ball = The height the ball falls in the time taken to reach the net from 20 meters + The height of the net = 7.5 m + 0.3 m = 7.8 m

The height at which Jeb needs to hit the ball = 7.8 m

4 0
3 years ago
Write the expression as a product of expressions.
scoray [572]

Answer:

a^2(ab^{3}-b^{2}-c^{2})

Step-by-step explanation:

Given

a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}

Required

Factor

a^{3}b^{3}-a^{2}b^{2}-a^{2}c^{2}

Factor out a^2

a^2(ab^{3}-b^{2}-c^{2})

<em>The expression cannot be further factored</em>

8 0
2 years ago
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