Answer with Step-by-step explanation:
We are given that
![f(x)=\mid x-9\mid](https://tex.z-dn.net/?f=f%28x%29%3D%5Cmid%20x-9%5Cmid)
when x<9
when ![x\geq 9](https://tex.z-dn.net/?f=x%5Cgeq%209)
LHD
![\lim_{x\rightarrow 9-}f'(x)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Crightarrow%209-%7Df%27%28x%29)
=![-\lim_{x\rightarrow 9-}(x-9)=-1](https://tex.z-dn.net/?f=-%5Clim_%7Bx%5Crightarrow%209-%7D%28x-9%29%3D-1)
RHD
![\lim_{x\rightarrow 9+}f'(x)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Crightarrow%209%2B%7Df%27%28x%29)
![=\lim_{x\rightarrow 9+}(x-9)=1](https://tex.z-dn.net/?f=%3D%5Clim_%7Bx%5Crightarrow%209%2B%7D%28x-9%29%3D1)
![LHD\neq RHD](https://tex.z-dn.net/?f=LHD%5Cneq%20RHD)
Hence, the function is not differentiable at x=9
A: Hope it helps Because…………………… I don’t really know I know it’s a I did this
The problem cannot be fully solved because you did provide the line on which the line is parallel/ but i can give you the steps on how to solve it. first solve the slope of the parallel line by
m = ( y2 - y1 ) / ( x2 - x1 )
then the slope of that line is equal to slope of line passing pooint ( -1 , 1)
then solve the y intercept of the line using
y = mx + b
where b is the y intercept
then you will have the equation of the line
I’m not the best with words but first you would have to treat the greater sign as a = sign. So..
-2x =6
/ /
-2 -2
X = -3
and then you would change the sign to a less than sign because you divided by a negative.