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Andru [333]
3 years ago
9

Select the correct answer

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0

Answer:

7 minutes

Step-by-step explanation:

When Jay and Kevin work together to clear the driveway of snow it takes an average of 14 minutes. If Jay or Kevin works alone to clear the driveway he can clean it in 21 minutes. In total if Jay works alone then he can clean the driveway by spending additional 7 minutes.

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The function f(x) is given by the set of ordered pairs.
NISA [10]

The true equation will be f(6) = 0. Then the correct option is C.

<h3>What is a function?</h3>

A statement, principle, or policy that creates the link between two variables is known as a function.

The function f(x) is given by the set of ordered pairs.

{(1,0), (–10,2), (0,6), (3,17), (–2,–1)}

Then the function can be written as

f(abscissa) = ordinate

Then the function will be

f(0) = 6

Then the correct option is C.

More about the function link is given below.

brainly.com/question/5245372

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2 years ago
Multiply the polynomials (x+2)(2x^2+9x+8)
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When you combine like terms you would get
2x^3+13x^2+26x+16
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I need help finding the values of the last boxes shown in the image.
Bingel [31]

The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid revolution on the X-axis?</h3>

The volume of a solid is the degree of space occupied by a solid object. If the axis of revolution is the planar region's border and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

In the graph, the given straight line passes through two points (0,0) and (2,8).

Therefore, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

where:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Thus, from the graph let assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8), we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

  • y = 0
  • x = 2
  • y = 4x

Similarly, the change in polar coordinates is:

  • x = rcosθ,
  • y = rsinθ

where;

  • x² + y² = r²  and dA = rdrdθ

Now

  • rsinθ = 0   i.e.  r = 0 or θ = 0
  • rcosθ = 2 i.e.   r  = 2/cosθ
  • rsinθ = 4(rcosθ)  ⇒ tan θ = 4;  θ = tan⁻¹ (4)

  • ⇒ r = 0   to   r = 2/cosθ
  •    θ = 0  to    θ = tan⁻¹ (4)

Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

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5 0
2 years ago
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