P+5= -2
p= -7 ( I subtracted 5 to both sides of the equation)
X=length
y=width
Area (rectangle)=length x width
we suggest this system of equations:
y=x/5
xy=9/20
solve this system of equations by substitution method:
x(x/5)=9/20
x²/5=9/20
Least common multiple=20
4x²=9
x²=9/4
x=⁺₋√(9/4)
we have two solutions:
x₁=-3/2 it does not validate
x₂=3/2 ⇒y=x/5=(3/2)/5=3/10
The dimensions of the lake are:
lengh=3/2 miles
width=3/10 miles
to check:
Area=3/2 miles x 3/10 miles=9/20 miles².
width is 1/5 the length of the lake ⇒ 3/10 miles=(3/2) /5 miles
Answer:
A. 7 in.
Step-by-step explanation:
We have been given that the perimeter of a rectangle is 16 inches. The equation that represents the perimeter of the rectangle is , where l represents the length of the rectangle and w represents the width of the rectangle.
We know that perimeter of rectangle is 2 times the sum of width and length of rectangle.




To be a rectangle length cannot be 8 as length and width of the rectangle is 8 inches.
Therefore, 7 inches the possible value for the length of the rectangle.
Answer:
It would be A.
Step-by-step explanation:
Because, 5 x 0 is 0, 5 x 1 is 5, 5 x 2 is 10, and so on. Its really just counting in 10s.