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Maurinko [17]
3 years ago
15

Question #5

Computers and Technology
2 answers:
BARSIC [14]3 years ago
8 0

Answer:

G18: Ensuring that a contrast ratio of at least 4.5:1 exists between text (and images ... 1.4.3, this technique describes the minimum contrast ratio for text that is less than ... 1.4.5, this technique relaxes the 7:1 contrast ratio requirement for text that is at ... If the background is a solid color (or all black or all white) then the relative

Explanation:

schepotkina [342]3 years ago
7 0

Answer:

2 to 1 edge 2021.

Explanation:

Your ratio can be reduced, just like a fraction. Here, 60 and 30 share the common factor of 30. So we can divide both numbers by 60 to get a ratio that means exactly the same thing as 60:30. This ratio will be 2:1.

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On laptops, wireless cards tend to be attached to which panel?
Arada [10]

Answer:

NONE of the above   to fix  wireless  cards to be attached to any panel

Explanation:

Basically, the WiFi receiver and transmitter are fixed in the mother of the laptop and fixed. In case if we   open the laptop if PCI slot is   available   and suitable WiFi card and able fit it  to size then   end user he or she  can fixed and  try

The hard drive is the backside of the laptop. If e place the WiFi system will able to boot.

LCD panel it is just displayed out the unit and  its  fixed in a different  place and connected to led or LCD panel

Palm rest it places where there is no slot available  

Ram panel if we fix WiFi card then the laptop will not start.

Better by USB dongle and use it.

5 0
3 years ago
What does a trademark indicate about a product?
AfilCa [17]

Answer:

A trademark refers to a recognizable insignia, expression or image that indicates an explicit item or benefit and lawfully separates it from every single other item.

Explanation:

5 0
4 years ago
What is the smallest v groove angle that can be welded useing the fca welding process?
vagabundo [1.1K]
The smallest v groove angle that can be welded using the FCA welding process is 20 degrees. Double v joints help for buckling forces especially in welding thicker metals.
3 0
3 years ago
Give a big-O estimate for the number of operations,
Kazeer [188]

Answer:

Explanation:

For the first iteration of i for loop 1 to n, the j for loop will run from 2 to n times. i.e. n-1 times.

For the second iteration of i for loop, the j for loop will run from 3 to n times. i.e. n-2 times.

From the third to the last iteration of i for loop, the j for loop will run n-1 to n times. i.e. 2 times.

From the second to the last iteration of i for loop, the j for loop will run from n to n times. i.e. 1 time.

For the last iteration of i for loop, the j for loop will run 0 times because i+1 >n.

Hence the equation looks like below:

1 + 2 + 3 + ...... + (n-2) + (n-1) = n(n-1)/2

So the number of total iterations is n(n-1)/2.

There are two operations per loop, i.e. Comparison and Multiplication, so the iteration is 2 * n(n-1)/2 = n ^2 - n

So f(n) = n ^ 2 - n

f(n) <= n ^ 2 for n > 1

Hence, The algorithm is O(n^2) with C = 1 and k = 1.

6 0
4 years ago
Help??????????????????
MrRa [10]

1-5

2-4

3-6

4-8

5-7

6-3

7-1

8-2

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3 years ago
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