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Lady_Fox [76]
3 years ago
8

Noah is solving an equation, and one of his moves is unacceptable. Here are the moves he made.

Mathematics
1 answer:
faust18 [17]3 years ago
3 0

Answer:

b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.

Step-by-step explanation:

The solution is correct up to the step 2x = 6x

2x = 6x

Subtract 2x from both sides.

0 = 4x

Divide both sides by 4.

x = 0

You cannot divide both sides by x since x could be zero, and in fact, it is.

Answer: b. When you divide both sides by 2x = 6x it could lead us to think that there is no solution while, in fact, the solution is x = 0.

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6x – 3x + 4 – 2x = x + one solution ,no solution, and many solution
Damm [24]

Answer:

6x – 3x + 4 – 2x = x

x+4=x

4=0

no solution

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
5+8+9+4+6-7-9-2-6*0/2
Kisachek [45]
The answer is 14, Hope this helps!
7 0
4 years ago
Read 2 more answers
worker a earns $7.90 per widget produced, produces 14 widgets per day, and works 10 hours per day. Worker b earns $9.00 per widg
Anni [7]
What are the statements 
3 0
3 years ago
What is the solution to this system of equations?
tia_tia [17]

Answer:

(2,4) is the solution of the equation.

Step-by-step explanation:

Basically, the solution is the two points intersecting at a point. So, (2,4) is the solution of the equation.

Hoped this helped.

8 0
2 years ago
Read 2 more answers
6) (after 2.3) Consider the infinite system of linear equations in two variables given by ax + by = 0 where (a, b) moves along t
Paraphin [41]

Answer:

Step-by-step explanation:

Given infinite system of linear equations is ax + by = 0

when (a,b) moves along unit circle in plane.

a) system having unique system (0, 0)

Since two of equation in thus system will be

1.x+0.y=0\\x=0

and

0.x+1.y=0\\y=0

It is clear that x = 0, y= 0 is the only solution

b) Linear independent solution in this system gives some set of solutions

1.x+0.y=0\\\x=0

and

0.x+1.y=0\\y=0

Vector form is

\left[\begin{array}{ccc}1&0\\0&1\end{array}\right] =I

c) for this equation if add 0x +0y = 0 to system , Nothing will change

Because [0,0] satisfies that equation

d) If one of the equation is ax + by = 0.00001

where 0.00001 is small positive number

so, the system will be inconsistent

Therefore, the system will have no solution.

6 0
3 years ago
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