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n200080 [17]
3 years ago
10

8/v + 9/x=y Solve for v​

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

The answer is v= -8x/-xy+9

Here is the step by step process (This is going to be long):

1.  9v+8x=vxy

Multiply both sides by vx

2.  9v+8x+−vxy=vxy+−vxy

−vxy+9v+8x=0

Add -vxy to both sides

3.  −vxy+9v+8x+−8x=0+−8x

−vxy+9v=−8x

Add -8x to both sides

4.  v(−xy+9)=−8x

Factor out the variable v

5.  v(-xy+9)/-xy+9 = -8x/-xy+9

v = -8x/-xy+9

Divide both sides by -xy+9

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Area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

                                             $=\frac{1}{4} \pi r^2 - \frac{1}{2} bh

                                             $=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times  12 \times 12

                                             $=36\pi -72

                                             $=36(\pi -2) square cm.

Area of the shaded region $=36(\pi -2) square cm

Using Pythagoras theorem,

AC^2=AB^2+BC^2

AC^2=12^2+12^2

AC^2=288

Taking square root on both sides of the equation, we get

AC= 12\sqrt 2 cm

Perimeter of the quadrant of a circle = \frac{1}{4} \times 2\pi r

                                                             $=\frac{1}{4} \times 2 \times \pi \times 12

                                                             $=6 \pi cm

Perimeter of the shaded region = 6 \pi + 12\sqrt 2 cm

                                                    =6 (\pi + 2\sqrt 2) cm

Hence area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

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