I need to find x thank you

Mathematics

2 answers:

DaniilM [7]3 years ago

7 0

Answer:

70 degrees

Step-by-step explanation:

First, remember that since two sides are congruent that this is an isosceles triangle. In an isosceles triangle, the two base angles (the angles opposite of the congruent sides) are congruent. That means to find x solve the equation 2x+40=180.

First, subtract 40 from both sides 2x=140, then divide by 2, x=70.

Therefore, x=70.

Georgia [21]3 years ago

3 0

180
180- 40=140
140 / 2= 70

You might be interested in

Help :( I’m not sure what the answer is

r-ruslan [8.4K]

Answer:

if it says greatest change then its 6:30 to 7:00

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

The roots of the quadratic equation $z^2 + az + b = 0$ are $2 - 3i$ and $2 + 3i$. What is $a+b$?

AlladinOne [14]

We know for our problem that the zeroes of our quadratic equation are $(2-3i)$ and $(2+3i)$ , which means that the solutions for our equation are $x=2-3i$ and $x=2+3i$ . We are going to use those solutions to express our quadratic equation in the form $a x^{2} +bx+c$ ; to do that we will use the zero factor property in reverse:
 $x=2-3i$
$x-2=-3i$
$x-2+3i=0$

 $x=2+3i$
$x-2=3i$
$x-2-3i=0$

Now, we can multiply the left sides of our equations:
 $(x-2+3i)(x-2-3i)= x^{2} -2x-3ix-2x+4+6i+3ix-6i-3^2i^2$
= $x^{2}-4x+4-9i^{2}$
= $x^{2} -4x+4+9$
= $x^{2} -4x+13$
Now that we have our quadratic in the form $a x^{2} +bx+c$ , we can infer that $a=1$ and $b=-4$ ; therefore, we can conclude that $a+b=1+(-4)=1-4=-3$ .