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jeyben [28]
4 years ago
5

Please help me with #4 i really need it?

Mathematics
1 answer:
Alexandra [31]4 years ago
7 0
Okay so for the similar two, draw one smaller and one bigger and then draw one that is completely different, but still a right triangle. Then explain how each triangle is different. I hope I helped! :)
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Please Help! A bag contains four green marbles and five yellow marbles. You randomly select three marbles. What is the probabili
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Answer:

A. 0.088

B. 0.048

C. 1.83 times

Step-by-step explanation:

From the question given above, the following data were obtained:

Green (G) = 4

Yellow (Y) = 5

Total = 4 + 5 = 9

A. Determination of the probability of selecting three green marbles with replacement.

Green (G) = 4

Yellow (Y) = 5

Total = 9

P(1st G) = 4/9

P(2nd G) = 4/9

P(3rd G) = 4/9

P(all G) = P(1st G) × P(2nd G) × P(3rd G)

P(all G) = 4/9 × 4/9 × 4/9

P(all G) = 64/729

P(all G) = 0.088

B. Determination of the probability of selecting three green marbles without replacement.

Green (G) = 4

Yellow (Y) = 5

Total = 9

P(1st G) = 4/9

P(2nd G) = 3/8

P(3rd G) = 2/7

P(all G) = P(1st G) × P(2nd G) × P(3rd G)

P(all G) = 4/9 × 3/8 × 2/7

P(all G) = 24/504

P(all G) = 0.048

C. Comparing probability of replacement and without replacement.

P(all G with replacement) = A = 0.088

P(all G without replacement) = B = 0.048

A/B = 0.088/0.048

A/B = 1.83

Cross multiply

A = 1.83 × B

Thus,

P(all G with replacement) = 1.83 × P(all G without replacement)

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