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3 years ago

Please help me with #4 i really need it?

Mathematics

1 answer:

Alexandra [31]3 years ago

7 0

Okay so for the similar two, draw one smaller and one bigger and then draw one that is completely different, but still a right triangle. Then explain how each triangle is different. I hope I helped! :)

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Solve equations -8x=88

Alexxx [7]

ANSWER:X=-11

Explanation

3 0

3 years ago

10 (w-4)=4 (w+4)+4w

eimsori [14]

Answer:

$w = 28$

Step-by-step explanation:

$10(w-4) = 4(w+4)+4w$

1. distribute

$10w - 40 = 4w +16 +4w$

2. collect like terms

$10w -4w - 4w = 40 +16$

3. solve

$2w = 56$

$w = 28$

8 0

3 years ago

Which contract costs more per month? An 18 month cable contract for $2070 or a 12 month contract at $1776? Which is the better d

Dafna1 [17]

Answer:

Contract A is cheaper because $115 per month is less than $148 per month

Step-by-step explanation:

To find the unit price we divide the total cost given by the total months given for each contract to find out the cost per month.

$2070/18 months = $115 per month

$1776/12 months = $148 per month

Contract A is cheaper because $115 per month is less than $148 per month

7 0

3 years ago

The passing yards for the top 5 quarterbacks in the country are 3,832, 3,779, 3,655, 3,642, and 3,579. Find the variance and sta

Leviafan [203]

First get the average passing yards:

(3,832 + 3,779 + 3,655 + 3,642 + 3,579) / 5 = 3,697.4

Now get the squared residuals for each quarterback's passing yards. That is, compute the difference between each data and the average, then square the result. For example,

(3,832 - 3,697.4)^2 = 134.6^2 = 18,117.2

For the others, you should get squared residuals of

6,658.56

1,797.76

3,069.16

14,018.6

Take the sum of the squared residuals, then - since this is a sample, and not a population of all quarterbacks - divide the sum by 5 - 1 = 4 to get the variance:

(18,117.2 + 6,658.56 + 1,797.76 + 3,069.16 + 14,018.6)/4 = 10,915.3

The standard deviation is just the square root of the variance:

√(10,915.3) ≈ 104.48

5 0

3 years ago

Read 2 more answers

A group of statistics students decided to conduct a survey at their university to find the average (mean) amount of time student

Butoxors [25]

Answer: $(21.541,\ 23.059)$