to find ur points, sub in any number for x and solve for f(x) or y lets let x = 0
y = 2/3(0) - 1 y = -1 so when x = 0, y = -1......so (0,-1) is one point
let x = 3 y = 2/3x - 1 y = 2/3(3) - 1 y = 6/3 - 1 y = 2 - 1 y = 1.....so when x = 3, y = 1....(3,1) <== another point
let x = 6 y = 2/3(6) - 1 y = 12/3 - 1 y = 4 - 1 y = 3....so when x = 6, y = 3.....(6,3) <== another point
let x = 9 y = 2/3(9) - 1 y = 18/3 - 1 y = 6 - 1 y = 5.....so when x = 9, y = 5....(9,5) <== another point
let x = 12 y = 2/3(12) - 1 y = 24/3 - 1 y = 8 - 1 y = 7...so when x = 12, y = 7....(12,7) <== ur fifth point
========================= f(x) = 2/3x - 1 y = 2/3x - 1....in y = mx + b form, ur b represents the y int. So ur y intercept(where the line cross the y axis) is (0,-1)
to find the x intercept, sub in 0 for y and solve for x y = 2/3x - 1 0 = 2/3x - 1 -2/3x = -1 x = -1 * -3/2 x = 3/2.....so ur x int (where ur line crosses the x axis) is (3/2,0)
now just plot all the points we just found, connect them, and they should make a straight line
