Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:

Step-by-step explanation:
You move the decimal place over 6 times for the first equation and 5 for the second equation.
Hope this helps! Have a great day! :)
Answer:
8
Step-by-step explanation:
4 times because if you count 10, 20, 30, 40, so it has to be 4
It is called the slope of the line