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Which statements are true about the ordered pair (10, 5) and the system of equations?

Alexeev081 [22]

Answer:

C

Step-by-step explanation:

We have the system of equations:

$\left\{\begin{array}{ll}2x-5y=-5 \\ x+2y=11\end{array}$

And an ordered pair (10, 5).

In order for an ordered pair to satisfy any system of equations, the ordered pair must satisfy both equations.

So, we can eliminate choices A and B. Satisfying only one of the equations does not satisfy the system of equations.

Let’s test the ordered pair. Substituting the values into the first equation, we acquire:

$2(10)-5(5)\stackrel{?}{=}-5$

Evaluate:

$20-25\stackrel{?}{=}-5$

Evaluate:

$-5\stackrel{\checkmark}{=} -5$

So, our ordered pair satisfies the first equation.

Now, we must test it for the second equation. Substituting gives:

$(10)+2(5)\stackrel{?}{=} 11$

Evaluate:

$20\neq 11$

So, the ordered pair does not satisfy the second equation.

Since it does not satisfy both of the equations, the ordered pair is not a solution to the system because it makes at least one of the equations false.

Therefore, our answer is C.

3 0

3 years ago

Dalton is playing a game in which the object is to obtain a 0 by adding the points scored during each round

Katen [24]

The answer to this question is 52

3 0

3 years ago

Write an equation of the line with the given slope and y-intercept

Vinil7 [7]

Answer:

y=mx+c

y=2x+9

Step-by-step explanation:

Slope(m)=2, y-intercept(c) =9

Substitute in the equation y=mx+c

5 0

3 years ago

Each of six jars contains the same number of candies. Alice moves half of the candies from the first jar to the second jar. Then

tino4ka555 [31]

Answer:

The number of candies in the sixth jar is 42.

Step-by-step explanation:

Assume that there are <em>x</em> number of candies in each of the six jars.

⇒ After Alice moves half of the candies from the first jar to the second jar, the number of candies in the second jar is:

$\text{Number of candies in the 2nd jar}=x+\fracx}{2}=\frac{3}{2}x$

⇒ After Boris moves half of the candies from the second jar to the third jar, the number of candies in the third jar is:

$\text{Number of candies in the 3rd jar}=x+\frac{3x}{4}=\frac{7}{4}x$

⇒ After Clara moves half of the candies from the third jar to the fourth jar, the number of candies in the fourth jar is:

$\text{Number of candies in the 4th jar}=x+\frac{7x}{4}=\frac{15}{8}x$

⇒ After Dara moves half of the candies from the fourth jar to the fifth jar, the number of candies in the fifth jar is:

$\text{Number of candies in the 5th jar}=x+\frac{15x}{16}=\frac{31}{16}x$

⇒ After Ed moves half of the candies from the fifth jar to the sixth jar, the number of candies in the sixth jar is:

$\text{Number of candies in the 6th jar}=x+\frac{31x}{32}=\frac{63}{32}x$

Now, it is provided that at the end, 30 candies are in the fourth jar.

Compute the value of <em>x</em> as follows:

$\text{Number of candies in the 4th jar}=40\\\\\frac{15}{8}x=40\\\\x=\frac{40\times 8}{15}\\\\x=\frac{64}{3}$

Compute the number of candies in the sixth jar as follows:

$\text{Number of candies in the 6th jar}=\frac{63}{32}x\\$

$=\frac{63}{32}\times\frac{64}{3}\\\\=21\times2\\\\=42$

Thus, the number of candies in the sixth jar is 42.

4 0

3 years ago

You are putting together a single elimination tournament. You have 4368 people sign up to compete. How many game will have to be

frosja888 [35]

Answer:

you will have to have 2,184 games to have a winner

Step-by-step explanation:

7 0

3 years ago

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