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3 years ago

15

Find the distance between (6, 0) and (10, 3).

2 answers:

Andre45 [30]3 years ago

8 0

Answer:

A

Algebra For what values of the variables must ABCD be a parallelogram?

B

23. A 2y + 2 B 24. B

(3x + 10)

(8x + 5)º

3x + 6

54°

D

С

D

A

Зу - 9 с

ly+4

yulyashka [42]3 years ago

6 0

A 5 units I believe

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Where did the 9/4 come from?

motikmotik

Answer:

Ok so this concept is kind of hard to explain, but basically the two equations are equal because you are adding 9/4 and then subtracting 9/4, so you just end up with 0. The reason you do that is so you can make the (x + 3/2)^2 part, which you wouldn't be able to do without the 9/4/

8 0

3 years ago

Read 2 more answers

The radius of a right circular cone is increasing at a rate of 1.4 in/s while its height is decreasing at a rate of 2.1 in/s. At

kow [346]

Given:

$\dfrac{dr}{dt}=1.4\text{ in/s}$

$\dfrac{dh}{dt}=-2.1\text{ in/s}$

To find:

The rate of change in volume at $r=120\text{ in. and }175\text{ in.}$

Solution:

We know that, volume of a cone is

$V=\dfrac{1}{3}\pi r^2h$

Differentiate with respect to t.

$\dfrac{dV}{dt}=\dfrac{1}{3}\pi\times \left[(r^2\dfrac{dh}{dt}) + h(2r\dfrac{dr}{dt})\right]$

Substitute the given values.

$\dfrac{dV}{dt}=\dfrac{1}{3}\times \dfrac{22}{7}\times \left[(120)^2(-2.1) +175(2)(120)(1.4)\right]$

$\dfrac{dV}{dt}=\dfrac{22}{21}\times \left[-30240+58800\right]$

$\dfrac{dV}{dt}=\dfrac{22}{21}\times 28560$

$\dfrac{dV}{dt}=29920$

Therefore, the volume of decreased by 29920 cubic inches per second.

6 0

3 years ago

Let |u| = 10 at an angle of 45° and |v| = 13 at an angle of 150°, and w = u + v. What is the magnitude and direction angle of w?

mixer [17]

Given:

$|u|=10$ at an angle of 45°.

$|v|=13$ at an angle of 150°.

$w=u+v$

To find:

Magnitude and direction angle of w.

Solution:

We have,

$w=u+v$

$\theta = 45^\circ, \phi = 150^\circ$

Now,

$u_x=|u|\cos \theta=10\cos 45^\circ=7.071$

$u_y=|u|\sin \theta=u_y=10\sin 45^\circ=7.071$

$v_x=|v|\cos \phi=13\cos 150^\circ=-11.25833$

$v_y=|v|\sin \phi=u_y=13\sin 150^\circ=6.5$

Using these information, we get

$R_x=u_x+v_x=7.071-11.25833=-4.18733$

$R_y=u_y+v_y=7.071+6.5=13.571$

$\text{Direction angle}=\tan^{-1}(\dfrac{R_y}{R_x})$

$\text{Direction angle}=\tan^{-1}(\dfrac{13.571}{-4.18733})$

$\text{Direction angle}=-72.8239$

$\text{Direction angle}=107.1476$

$\text{Direction angle}\approx 107.1$

Now,

$|w|=\sqrt{(|u|\cos \theta +|v|\cos \phi)^2+(|u|\sin \theta +|v|\sin \phi)^2}$

$|w|=\sqrt{(10\cos(45)+13\cos 150)^2+(10\sin(45)+13\sin 150)^2}$

$|w|=\sqrt{(10(\dfrac{1}{\sqrt{2}})+13(-\dfrac{\sqrt{3}}{2}))^2+(10(\dfrac{1}{\sqrt{2}})+13(\dfrac{1}{2}))^2}$

$|w|=14.20236$

$|w|\approx 14.20236$

Therefore, the correct option is D.

4 0

3 years ago

Read 2 more answers

A line's y-intercept is -9, and its slope is 1. What is its equation in slope-intercept form?

azamat

Answer:

y=x-9

Step-by-step explanation:

7 0

3 years ago

Please help quick explain

den301095 [7]

Answer:

Step-by-step explanation:

3/5, 12/20

7 0

3 years ago