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docker41 [41]
2 years ago
13

0=(2y−1)(8−y) Let y=u, y=d. What is the value of u×d

Mathematics
2 answers:
gulaghasi [49]2 years ago
5 0

Answer:

The value of uxd=4

Step-by-step explanation:

since  y=u, y=d, y=y

y=1/2 and 8

2y-1=0

2y=1

y=1/2

8-y=0

8=y

1/2*8=4

Goryan [66]2 years ago
3 0

Answer:

4

Step-by-step explanation:

0=(2y−1)(8−y)

Using the zero product property

2y-1 =0    8-y =0

2y =1     8=y

y =1/2  y= 8

Let y=u, y=d

u = 1/2    d = 8

We want the value of u*d

u*d = 1/2 *8 = 4

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