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anzhelika [568]
3 years ago
12

Matt is the catcher for his school's baseball team. The catcher must be able to throw from home plate to second base. What is th

e distance from home plate to second base?
127.3 feet
127.3 feet

180 feet
180 feet

90 feet
90 feet

254.5 feet
254.5 feet
Mathematics
2 answers:
Oduvanchick [21]3 years ago
4 0

Answer:

Step-by-step explanation:

127.3

never [62]3 years ago
4 0
127.3 the first option
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The value of y when x is 8 is b. 2/3
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6 0
3 years ago
Find the area of the shaded region.
kolbaska11 [484]

Answer:

\boxed{ \tt\longrightarrow \: Area \:  Of  \: Shaded \:  region  \: =\boxed{ \tt 39  \: in²}}

Step-by-step explanation:

<u>Given:</u>

The Dimensions of Parallelogram are 12 in.(Base) and 7 in.(Height)

<em>And,</em>

The Dimensions of Rectangle are 9 in.(Length) and 5 in.(Breadth).

<u>To Find</u>:

The Area of Shaded region

<u>Solution:</u>

When the dimensions of parallelogram and the dimensions of rectangle are given, we need to find the Shaded region using this formula:

\boxed{\tt \longrightarrow Area  = (Parallelogram  - Rectangle)}

We know that the formula of Parallelogram is base*height[b×h] and the formula of rectangle is length*breadth[l*b] .

\tt\longrightarrow \: Area =B×h-l×b

Put their values accordingly:

\longrightarrow  \tt Area = (12 \times 7 - 9 \times 5)in {}^{2}

<u>Simplify it.</u>

<em>[</em><em>Follow BODMAS Rule strictly while </em><em>simplifying]</em>

\tt\longrightarrow \: Area = (84 - 45 ) in {}^{2}

\tt\longrightarrow \: Area = 39 \:  {in}^{2}

Hence, the Area of Shaded region would be 39 in² or 39 sq. in. .

\rule{225pt}{2pt}

I hope this helps!

8 0
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Answer:

I believe it's D.

Step-by-step explanation:

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Hope This Helps!       Have A Nice Day!!

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What is the result of adding
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Answer: You get an answer?

Step-by-step explanation:

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