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Radda [10]
3 years ago
9

Sixty photos taken at a photo shoot are in black and white. If this represents 15 percent of the total number of photos taken, w

hich equation can be used to find the total number of photos?
StartFraction 60 times 4 Over 15 times 4 EndFraction = StartFraction 240 Over 60 EndFraction
StartFraction 60 divided by 4 Over 100 divided by 4 EndFraction = StartFraction 15 Over 25 EndFraction
StartFraction 60 divided by 10 Over 100 divided by 10 EndFraction = StartFraction 6 Over 10 EndFraction
StartFraction 15 times 4 Over 100 times 4 EndFraction = StartFraction 60 Over 400 EndFraction
Mathematics
2 answers:
Oduvanchick [21]3 years ago
5 0

If this represents 15 percent of the total number of photos taken, which equation can be used to find the total number of photos? A. 60×4/15×4 = 240/60.

Lubov Fominskaja [6]3 years ago
3 0

Answer:

other guy right

Step-by-step explanation:

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We can compute the integral directly: we have

\begin{cases}x(t)=\sin t\\y(t)=\cos t\\z(t)=\sin(2t)\end{cases}\implies\begin{cases}\mathrm dx=\cos t\,\mathrm dt\\\mathrm dy=-\sin t\,\mathrm dt\\\mathrm dz=2\cos(2t)\,\mathrm dt\end{cases}

Then the integral is

\displaystyle\int_C(y+9\sin x)\,\mathrm dx+(z^2+4\cos y)\,\mathrm dy+x^3\,\mathrm dz

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You could also take advantage of Stokes' theorem, which says the line integral of a vector field \vec F along a closed curve C is equal to the surface integral of the curl of \vec F over any surface S that has C as its boundary.

In this case, the underlying field is

\vec F(x,y,z)=\langle y+9\sin x,z^2+4\cos y,x^3\rangle

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\vec s(u,v)=\langle u\cos v,u\sin v,2u^2\cos v\sin v\rangle=\langle u\cos v,u\sin v,u^2\sin(2v)\rangle

with 0\le u\le1 and 0\le v\le2\pi.

Note that when viewed from above, C has negative orientation (a particle traveling on this path moves in a clockwise direction). Take the normal vector to S to be pointing downward, given by

\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=\langle2u^2\sin v,2u^2\cos v,-u\rangle

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\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S\mathrm{curl}\vec F(x,y,z)\cdot\mathrm d\vec S

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Both integrals are kind of tedious to compute, but personally I prefer the latter method. Either way, you end up with a value of \boxed\pi.

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3 years ago
Can someone help me? I don't understand how to do this.
almond37 [142]

it should be 42percent I didn't really know my bad

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